Home / iGCSE Biology (0610) 2.2 Size of specimens iGCSE Style Questions Paper 2

iGCSE Biology (0610) 2.2 Size of specimens iGCSE Style Questions Paper 2

Question

The image shows a pollen grain from a grass plant.

Pollen grain

The image has a length of 60mm. The actual length of the pollen grain is 500 μm. What is the magnification of the pollen grain?

A) ×0.12
B) ×30
C) ×120
D) ×30 000

▶️ Answer/Explanation
Solution

Ans: C

Magnification is calculated using the formula:

\[ \text{Magnification} = \frac{\text{Image Size}}{\text{Actual Size}} \]

First, convert units for consistency:
Image Size = 60 mm = 60,000 μm
Actual Size = 500 μm
Thus, Magnification = \(\frac{60,000}{500} = 120\).

Therefore, the correct answer is C (×120).

Question

The diagram shows an epidermal cell from an onion plant. The distance between X and Y on the diagram is 60 mm. The actual length of the cell between X and Y is 150 μm.

Onion Epidermal Cell

What is the magnification of the cell?

A) ×40
B) ×250
C) ×400
D) ×2500

▶️ Answer/Explanation
Solution

Ans: C

Magnification is calculated using the formula:

\[ \text{Magnification} = \frac{\text{Image Size}}{\text{Actual Size}} \]

First, convert both measurements to the same unit (micrometers, μm):

\[ \text{Image Size} = 60 \, \text{mm} = 60,000 \, \mu\text{m} \]

\[ \text{Actual Size} = 150 \, \mu\text{m} \]

Now, plug the values into the formula:

\[ \text{Magnification} = \frac{60,000}{150} = 400 \]

Thus, the magnification is ×400, which corresponds to option C.

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