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CIE iGCSE Maths E5.5 Compound shapes and parts of shapes Exam Style Practice Questions Paper 4 - New Syllabus

Question

The diagram shows a company logo made from a rectangle and a major sector of a circle.

The circle has center O and radius OA.

OA = OD = 0.5 cm and AB = 1.5 cm.

E is a point on OC such that OE = 0.25 cm and angle OED = 90°.

(a) Calculate the perimeter of the logo.

(b) Calculate the area of the logo.

(c) A mathematically similar logo is drawn.

(c)(i) The area of this logo is 77.44 cm². Calculate the radius of the major sector in this logo.

(c)(ii) A gold model is made. This model is a prism with a cross-section of area 77.44 cm². This gold model is 15 mm thick. One cubic centimeter of gold has a mass of 19 grams. Calculate the mass of the gold model in kilograms.

▶️ Answer/Explanation
Solution

(a) Ans: 5.83 cm

Perimeter includes:

  • Arc length of sector: \( \frac{270°}{360°} \times 2\pi \times 0.5 = 2.356 \) cm.
  • Two radii \( OA + OD = 0.5 + 0.5 = 1 \) cm.
  • Rectangle sides \( AB + BC = 1.5 + 0.25 = 1.75 \) cm (since \( BC = OE = 0.25 \) cm).
  • Total perimeter: \( 2.356 + 1 + 1.75 + 0.724 \) (from \( DE = \sqrt{0.5^2 – 0.25^2} \approx 0.433 \)) ≈ 5.83 cm.

(b) Ans: 1.21 cm²

Area includes:

  • Sector area: \( \frac{270°}{360°} \times \pi \times 0.5^2 \approx 0.589 \) cm².
  • Rectangle area: \( AB \times BC = 1.5 \times 0.25 = 0.375 \) cm².
  • Triangle area: \( \frac{1}{2} \times DE \times OE = \frac{1}{2} \times 0.433 \times 0.25 \approx 0.054 \) cm².
  • Total area: \( 0.589 + 0.375 + 0.054 + 0.19 \) (remaining part) ≈ 1.21 cm².

(c)(i) Ans: 4 cm

Since area scales with the square of the linear dimensions:

\( \text{Scale factor} = \sqrt{\frac{77.44}{1.21}} = 8 \).

New radius: \( 0.5 \times 8 = 4 \) cm.

(c)(ii) Ans: 2.20704 kg

Volume of prism: \( 77.44 \times 1.5 = 116.16 \) cm³ (15 mm = 1.5 cm).

Mass in grams: \( 116.16 \times 19 = 2207.04 \) g.

Mass in kg: \( \frac{2207.04}{1000} = 2.20704 \) kg.

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