iGCSE Mathematics (0580) - C1.11 Ratio and proportion - Exam Style Questions Paper 1- New Syllabus
▶️ Answer/Explanation
If \(\dfrac{3}{5}\) of the total = 75, then \(\dfrac{1}{5}\) of the total = \(75 \div 3 = 25\).
Therefore the total number of students = \(25 \times 5 = 125\).
Alternatively: Total \(= 75 \div \dfrac{3}{5} = 75 \times \dfrac{5}{3} = 125\).
✅ Answer: \(125\)
Therefore the total number of students = \(25 \times 5 = 125\).
Alternatively: Total \(= 75 \div \dfrac{3}{5} = 75 \times \dfrac{5}{3} = 125\).
✅ Answer: \(125\)
▶️ Answer/Explanation
The smallest share corresponds to the ratio part of 2, and this equals \(\$120\), so 1 part \(= \$60\).
The total number of parts is \(10 + 3 + 2 = 15\).
Therefore \(n = 15 \times 60 = 900\).
✅ Answer: \(n = 900\)
▶️ Answer/Explanation
Jo’s share of the ratio is \(7\) parts, which equals \(\$1400\).
Find the value of one part by dividing: \(1400 \div 7 = \$200\).
The total number of ratio parts is \(4 + 7 + 13 = 24\).
The total amount of money is \(24 \times 200 = 4800\).
✅ Answer: \(\$4800\)