(a) The table shows some information about the opening hours of a café. The café opens 4 days a week.
Complete the table.
(b)(i) A waiter works 29 hours a week in the café.
He is paid $9.50 per hour.
He is paid for 52 weeks of the year.
Work out his total pay for the year.
(ii) The chef is paid 32% more than the waiter per hour
Work out how much the chef is paid per hour
(c) Here is part of the café’s menu.
Raj buys 2 cups of coffee, 1 cup of tea and 3 slices of pizza
Calculate the change he receives from $20.
(d) The chef records the types of baguettes the café sells in one day.
(i) Complete the frequency table to show this information.
(ii) On the grid, draw a bar chart to show this information.
▶️ Answer/Explanation
(a) Ans:
Thursday: Closing Time = 4:30 PM, Hours Open = 8.5
Friday: Closing Time = 4:00 PM
Saturday: Hours Open = 8
Sunday: Opening Time = 10:30 AM
(b)(i) Ans: $14,326
Weekly pay = 29 × $9.50 = $275.50
Yearly pay = $275.50 × 52 = $14,326
(b)(ii) Ans: $12.54
32% of $9.50 = $3.04
Chef’s pay = $9.50 + $3.04 = $12.54 per hour
(c) Ans: $1.60
Total cost = (2 × $2.50) + $2.30 + (3 × $3.70) = $18.40
Change = $20 – $18.40 = $1.60
(d)(i) Ans:
Cheese: 7
Ham: 4
Tuna: 11
(d)(ii) Ans:
Correct bar chart showing:
Cheese (7), Ham (4), Tuna (11)
(a) 1 mile = 1.609344 kilometres. Change 6 miles into metres. Give your answer correct to the nearest metre.
(b) (i) The bearing of a boat from a harbour is 322°. Work out the bearing of the harbour from the boat.
(ii) The boat is 12km from the harbour. At 2.30 pm the boat starts to sail to the harbour. The speed of the boat is 5km/h. Work out the time the boat arrives at the harbour.
(c) (i) The scale drawing shows the positions of Shakti’s house (S) and Mairi’s house (M) on a map (scale: 1cm = 4km). Measure the bearing of M from S.
(ii) Another map (scale: 1cm = 5km) shows Shakti’s house (S). Mark Mairi’s house (M) on this map.
▶️ Answer/Explanation
(a) Answer: 9656 metres
6 miles × 1.609344 km/mile × 1000 m/km = 9656.064m ≈ 9656m
(b)(i) Answer: 142°
Reverse bearing = (322° – 180°) = 142° (subtract 180° for opposite direction)
(b)(ii) Answer: 4.54 pm
Time = Distance/Speed = 12km ÷ 5km/h = 2.4h (2h24m) → 2:30pm + 2h24m = 4:54pm
(c)(i) Answer: 107°
Measure angle clockwise from North line to SM line in given diagram.
(c)(ii) Answer: [Marked position]
Using original bearing/distance, plot M at correct scaled position (1cm = 5km) relative to S.