iGCSE Mathematics (0580) - C1.15 Time- Exam Style Questions Paper 3- New Syllabus
▶️ Answer/Explanation
First, calculate the arrival time in Seattle’s local time by adding the flight duration: $0730 + 10 \text{ hours } 55 \text{ minutes} = 1825$ on Tuesday.
Next, adjust for the time zone difference by adding the $16$ hours ahead that Seoul is compared to Seattle: $1825 + 1600 = 3425$.
Since a day has $24$ hours, subtract $2400$ to find the time on the next day: $3425 – 2400 = 1025$.
Because the time rolled over past midnight ($2400$), the arrival day shifts from Tuesday to Wednesday.
✅ Answer: Wednesday and 1025
Next, adjust for the time zone difference by adding the $16$ hours ahead that Seoul is compared to Seattle: $1825 + 1600 = 3425$.
Since a day has $24$ hours, subtract $2400$ to find the time on the next day: $3425 – 2400 = 1025$.
Because the time rolled over past midnight ($2400$), the arrival day shifts from Tuesday to Wednesday.
✅ Answer: Wednesday and 1025
▶️ Answer/Explanation
(a) Answer: 9656 metres
6 miles × 1.609344 km/mile × 1000 m/km = 9656.064m ≈ 9656m
(b)(i) Answer: 142°
Reverse bearing = (322° – 180°) = 142° (subtract 180° for opposite direction)
(b)(ii) Answer: 4.54 pm
Time = Distance/Speed = 12km ÷ 5km/h = 2.4h (2h24m) → 2:30pm + 2h24m = 4:54pm
(c)(i) Answer: 107°
Measure angle clockwise from North line to SM line in given diagram.
(c)(ii) Answer: [Marked position]
Using original bearing/distance, plot M at correct scaled position (1cm = 5km) relative to S.