iGCSE Mathematics (0580) - C2.1 Introduction to algebra- Exam Style Questions Paper 1- New Syllabus
▶️ Answer/Explanation
(a)
First, convert the total cost to cents: \(\$3.45 = 345 \text{ cents}\).
The cost of \(3\) apples is \(3 \times 40 = 120 \text{ cents}\).
The remaining cost goes toward the \(5\) peaches: \(345 – 120 = 225 \text{ cents}\).
To find the cost of \(1\) peach, divide by \(5\): \(225 \div 5 = 45 \text{ cents}\).
✅ Answer: \(45 \text{ cents}\)
(b)
The cost of \(x\) pears is \(55 \times x = 55x \text{ cents}\).
The cost of \(y\) bananas is \(36 \times y = 36y \text{ cents}\).
The total cost is the sum of both.
✅ Answer: \(55x + 36y\)
▶️ Answer/Explanation
(a) If one single ticket costs $\$18$, then for $t$ tickets, we simply multiply the cost per ticket by the number of tickets, which gives us $18 \times t$ or simply $18t$.
(b) To find the total number of items in a group, we add up the individual parts. Here, we add the $n$ red balls and the $16$ green balls together to get the expression $n + 16$.
✅ Answer:
(a) $18t$
(b) $n + 16$
(b) To find the total number of items in a group, we add up the individual parts. Here, we add the $n$ red balls and the $16$ green balls together to get the expression $n + 16$.
✅ Answer:
(a) $18t$
(b) $n + 16$
▶️ Answer/Explanation
Answer: \( \frac{3}{10}n \)
Solution:
1. Total marbles given away: \[ \frac{n}{5} + \frac{n}{2} = \frac{2n}{10} + \frac{5n}{10} = \frac{7n}{10} \] 2. Marbles remaining: \[ n – \frac{7n}{10} = \frac{10n}{10} – \frac{7n}{10} = \frac{3n}{10} \] Simplified expression: \( \frac{3}{10}n \)
1. Total marbles given away: \[ \frac{n}{5} + \frac{n}{2} = \frac{2n}{10} + \frac{5n}{10} = \frac{7n}{10} \] 2. Marbles remaining: \[ n – \frac{7n}{10} = \frac{10n}{10} – \frac{7n}{10} = \frac{3n}{10} \] Simplified expression: \( \frac{3}{10}n \)
