Home / iGCSE Mathematics (0580) – C2.2 Algebraic manipulation- Exam Style Questions Paper 1

iGCSE Mathematics (0580) - C2.2 Algebraic manipulation- Exam Style Questions Paper 1- New Syllabus

Question

Expand and simplify.

\((x + 3)(x – 2)\)

Most-appropriate topic codes (Cambridge IGCSE Mathematics 0580):

TOPIC C2.2 Algebraic manipulation: Expand products of algebraic expressions — includes products of two brackets involving one variable (Core)
▶️ Answer/Explanation
Expand using FOIL (First, Outer, Inner, Last):
\[(x+3)(x-2) = x^2 – 2x + 3x – 6\]
Collect like terms: \(-2x + 3x = +x\).
\[= x^2 + x – 6\]
Answer: \(x^2 + x – 6\)

Question

(a) Simplify. \(\quad 3y – 4y + 2y\)

(b) Solve.
(i) \(x + 5 = 19\)
(ii) \(6x – 5 = 7\)

Most-appropriate topic codes (Cambridge IGCSE Mathematics 0580):

Topic C2.2 Algebraic manipulation: Simplify expressions by collecting like terms (Core)
Topic C2.5 Equations: Solve linear equations in one unknown (Core)
▶️ Answer/Explanation

(a)
Combine the like terms by adding their coefficients:
\(3 – 4 + 2 = 1\).
Thus, the expression simplifies to \(1y\) or just \(y\).
Answer: \(y\)

(b)(i)
Subtract \(5\) from both sides of the equation:
\(x = 19 – 5\)
\(x = 14\)
Answer: \(x = 14\)

(b)(ii)
Add \(5\) to both sides of the equation:
\(6x = 7 + 5\)
\(6x = 12\)
Divide both sides by \(6\):
\(x = 12 \div 6 = 2\)
Answer: \(x = 2\)

Question

(a) Factorise completely.
18x² – 12x

(b) Expand and simplify.
(x + 5)(x – 3)

▶️ Answer/Explanation
Solution

Ans:

(a) 6x(3x – 2) (take out common factor 6x)

(b) x² + 2x – 15 (use FOIL method: x×x + x×(-3) + 5×x + 5×(-3))

Question

The diagram shows a rectangle with length \(3x-12\) and width \(x+7\).

Find an expression for the perimeter of the rectangle.

Give your answer in its simplest form.

▶️ Answer/Explanation
Solution

Ans: \(8x-10\) or \(2(4x-5)\)

The perimeter \( P \) of a rectangle is calculated using the formula:

\[ P = 2(\text{Length} + \text{Width}) \]

Substitute the given expressions for length (\(3x – 12\)) and width (\(x + 7\)):

\[ P = 2((3x – 12) + (x + 7)) \]

Simplify the expression inside the parentheses:

\[ P = 2(4x – 5) \]

Finally, expand to get the simplest form:

\[ P = 8x – 10 \]

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