iGCSE Mathematics (0580) - C2.4 Indices II- Exam Style Questions Paper 1- New Syllabus
Question
(a) \(a^{8} \times a^{x} = a^{15}\)
Find the value of \(x\).
(b) \(\left(b^{7}\right)^{y} = b^{21}\)
Find the value of \(y\).
Most-appropriate topic codes (Cambridge IGCSE Mathematics 0580):
▶️ Answer/Explanation
(a)
When multiplying powers of the same base, add the indices: \(a^8 \times a^x = a^{8+x}\).
Setting the exponent equal to 15: \(8 + x = 15\), so \(x = 7\).
✅ Answer: \(x = 7\)
(b)
When raising a power to a power, multiply the indices: \((b^7)^y = b^{7y}\).
Setting the exponent equal to 21: \(7y = 21\), so \(y = 3\).
✅ Answer: \(y = 3\)
Question
Simplify.
(a) $y^{4} \times y^{6}$
(b) $\frac{p^{5}}{p^{8}}$
(c) $(w^{4})^{3}$
Most-appropriate topic codes (Cambridge IGCSE Mathematics 0580):
▶️ Answer/Explanation
(a) When multiplying terms with the same base, we keep the base and add the exponents: $y^{4+6} = y^{10}$.
(b) When dividing terms with identical bases, we subtract the exponent of the denominator from the numerator: $p^{5-8} = p^{-3}$, which can also be neatly expressed as $\frac{1}{p^3}$.
(c) For a power raised to another power, we multiply the indices together: $w^{4 \times 3} = w^{12}$.
Answers:
(a) $y^{10}$
(b) $\frac{1}{p^{3}}$ or $p^{-3}$
(c) $w^{12}$
Simplify.
(a) \( n^5 \times n \)
(b) \( 8x^6 \div 2x^2 \)
▶️ Answer/Explanation
(a) Ans: \( n^6 \)
When multiplying with the same base, add the exponents: \( n^5 \times n^1 = n^{5+1} = n^6 \)
(b) Ans: \( 4x^4 \)
Divide coefficients (8÷2=4) and subtract exponents (6-2=4): \( 4x^{6-2} = 4x^4 \)
