CIE iGCSE Maths C8.3 Probability of combined events Exam Style Practice Questions- Paper 3
(a) Li spins a fair 6-sided spinner numbered $1$ to $6$.
On the probability scale, draw an arrow $(\downarrow )$ to show the probability that the spinner lands on the number 2.
![]()
(ii) Find the probability that the spinner lands on a prime number.
(iii) Find the probability that the spinner lands on the number 7.
(b) A bag contains 3 red balls and 12 green balls. Li picks a ball at random.
Find the probability that it is a green ball. Give your answer as a fraction in its simplest form.
(c) Li spins two fair 4-sided spinners, each numbered 1 to 4. The two numbers are multiplied to give the score.
![]()
Find the probability that the score is:
(i) an even number
(ii) an integer
(iii) at least 10.
(d) A bag contains red discs and blue discs. The probability that a disc picked at random is red is $\frac{1}{5}$. Li picks a disc at random, notes its colour and then replaces it in the bag. She then picks another disc at random.
(i) Complete the tree diagram.
![]()
(ii) Work out the probability that both of the discs she picks are blue.
▶️ Answer/Explanation
(a)(i) Ans: Arrow at $\frac{1}{6}$
The spinner has 6 sides, so the probability of landing on 2 is $\frac{1}{6}$.
![]()
(a)(ii) Ans: $\frac{1}{2}$
Prime numbers between 1 and 6: 2, 3, 5. There are 3 primes out of 6, so the probability is $\frac{3}{6} = \frac{1}{2}$.
(a)(iii) Ans: $0$
The spinner is numbered 1 to 6, so landing on 7 is impossible.
(b) Ans: $\frac{4}{5}$
Total balls: $3 + 12 = 15$. Green balls: 12. Probability: $\frac{12}{15} = \frac{4}{5}$.
(c)(i) Ans: $\frac{3}{4}$
Even scores: 2, 4, 6, 8, 12, 16. Favored outcomes: 12. Total outcomes: 16. Probability: $\frac{12}{16} = \frac{3}{4}$.
(c)(ii) Ans: $1$
All possible scores are integers, so the probability is $1$.
(c)(iii) Ans: $\frac{3}{16}$
Scores ≥ 10: 12, 16. Favored outcomes: 3. Probability: $\frac{3}{16}$.
(d)(i)
Probability of red: $\frac{1}{5}$. Probability of blue: $1 – \frac{1}{5} = \frac{4}{5}$.
![]()
(d)(ii) Ans: $\frac{16}{25}$
Probability both discs are blue: $\frac{4}{5} \times \frac{4}{5} = \frac{16}{25}$.
