Home / iGCSE Mathematics (0580) – C2.9 Graphs in practical situations- Exam Style Questions Paper 3

iGCSE Mathematics (0580) - C2.9 Graphs in practical situations- Exam Style Questions Paper 3- New Syllabus

IGCSE Mathematics(0580) Practice Questions Paper 3 - All Chapters

Question

Bob travels from town A to town B.
The travel graph shows his journey.

(a) Between which two times did Bob stop for a rest?
Explain how you know.

(b) Calculate Bob’s average speed, in km/h, for the whole journey.

Most-appropriate topic codes (Cambridge IGCSE Mathematics 0580):

• C2.9 Graphs in practical situations
▶️ Answer/Explanation

(a)
Bob is resting when his distance from town A is not changing (represented by the horizontal line segment on the graph). Reading the x-axis gives the times.
✅ Answer: Between $10:30$ and $11:15$ because the line is horizontal (distance remains the same).

(b)
Total distance = $625$ km.
Total time from $08:00$ to $14:15$ is $6$ hours and $15$ minutes = $6.25$ hours.
Average speed = $\frac{\text{Total Distance}}{\text{Total Time}} = \frac{625}{6.25} = 100$ km/h.
✅ Answer: $100$ km/h

Question

A railway line has three stations, Town, Port and Cove.
Train A leaves Town for Cove and train B leaves Cove for Town.
Both trains stop at Port.

(a) Write down the time that train B leaves Cove.

(b) Write down how long train A stops at Port.

(c) How many more minutes does train A take to complete the whole journey than train B?

(d) Write down the time that the two trains pass each other.

(e) Work out the average speed of train A between Town and Cove in kilometres per hour.

▶️ Answer/Explanation
Solution

(a) 14:10

From the graph, train B’s departure time from Cove is clearly marked as 14:10.

(b) 4 minutes

Train A arrives at Port at 14:20 and departs at 14:24, so the stop time is 4 minutes.

(c) 2 minutes

Train A takes 40 minutes (14:00-14:40), train B takes 38 minutes (14:10-14:48). The difference is 2 minutes.

(d) 14:25

The trains pass each other at the point where their lines cross on the graph, which is at 14:25.

(e) 34.5 km/h

Total distance is 23 km, time taken is 40 minutes (2/3 hours). Speed = distance/time = 23/(2/3) = 34.5 km/h.

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