Question
$y$ is inversely proportional to $\sqrt{x}$ and $x$ is directly proportional to $w^2$.
When $w = 12$, $y = 12$.
Find $y$ in terms of $w$.
▶️ Answer/Explanation
Solution
$y = \frac{144}{w}$
1. First relationship: $y = \frac{k}{\sqrt{x}}$
2. Second relationship: $x = mw^2$
3. Combine: $y = \frac{k}{\sqrt{mw^2}} = \frac{k}{\sqrt{m}w}$
4. Substitute w=12, y=12 to find k/√m = 144
Question
$w$ is proportional to the square root of $y$.
$y$ is inversely proportional to $x$.
When $x = 4$, $y = 16$ and $w = 8$.
Find $w$ in terms of $x$.
▶️ Answer/Explanation
Solution
Ans: $\frac{16}{\sqrt{x}}$
First find $y = \frac{k}{x}$ → $16 = \frac{k}{4}$ → $k = 64$, so $y = \frac{64}{x}$.
Then $w = m\sqrt{y}$ → $8 = m\sqrt{16}$ → $m = 2$.
Substitute: $w = 2\sqrt{\frac{64}{x}} = \frac{16}{\sqrt{x}}$.