Home / iGCSE Mathematics (0580) :E1.12 Calculate a given percentage of a quantity.iGCSE Style Questions Paper 4

iGCSE Mathematics (0580) :E1.12 Calculate a given percentage of a quantity.iGCSE Style Questions Paper 4

Question

Dhanu has a model railway.

(a) He has a train that consists of a locomotive and 4 coaches.
The mass of the locomotive is 87g and the mass of each coach is 52g.
(i) Work out the total mass of the train.
(ii) Work out the mass of the locomotive as a percentage of the total mass of the train.

(b) The train is 61cm long and travels at a speed of 18cm/s.
It takes 4 seconds for the whole of the train to cross a bridge.
Calculate the length of the bridge.

(c) A new locomotive costs \($64\).
Calculate the cost of the locomotive in rupees when the exchange rate is 1 rupee = \($0.0154\).
Give your answer correct to the nearest 10 rupees.

(d) The cost of a railway magazine increases by 12.5% to \($2.70\).
Calculate the cost of the magazine before this increase.

(e) Dhanu plays with his model railway from 0650 to 11 15.
He then rides his bicycle for 3 hours.
Find the ratio time playing with model railway : time riding bicycle.
Give your answer in its simplest form.

(f) The value of Dhanu’s model railway is \($550\).
This value increases exponentially at a rate of r% per year.
At the end of 5 years the value will be \($736\).
Calculate the value of r.

▶️ Answer/Explanation
Solution

(a)(i) Ans: 295 g

Total mass = Locomotive + 4 Coaches = \(87 + 4 \times 52 = 87 + 208 = 295\) g.

(a)(ii) Ans: 29.5%

Percentage = \(\frac{87}{295} \times 100 \approx 29.5\%\).

(b) Ans: 11 cm

Total distance covered = Speed × Time = \(18 \times 4 = 72\) cm. Bridge length = Total distance – Train length = \(72 – 61 = 11\) cm.

(c) Ans: 4160 rupees

Cost in rupees = \(\frac{64}{0.0154} \approx 4155.84\), rounded to nearest 10 is 4160.

(d) Ans: $2.40

Original cost = \(\frac{2.70}{1.125} = 2.40\).

(e) Ans: 53 : 36

Time playing = 4 hours 25 minutes = 265 minutes. Time cycling = 3 hours = 180 minutes. Ratio = \(265 : 180 = 53 : 36\).

(f) Ans: 6.00%

Using exponential growth formula: \(736 = 550(1 + \frac{r}{100})^5\). Solving gives \(r \approx 6.00\%\).

Question

These are the rates charged by a painter, a plumber and an electrician who do some work for Mr Sharma.

Worker rates

(a) The painter works for 7 hours. Calculate the amount Mr Sharma pays the painter.

(b) Mr Sharma pays the plumber \($252.\) Calculate how many hours the plumber works.

(c) Mr Sharma pays the electrician \($224.\) Calculate how many hours the electrician works.

(d) Write down the ratio of the amount Mr Sharma pays to the painter, the plumber and the electrician. Give your answer in its lowest terms.

▶️ Answer/Explanation
Answers:

(a) $245

Solution: Painter’s rate = $35/hour. For 7 hours: 35 × 7 = $245.

(b) 8 hours

Solution: Plumber’s rate = $31.50/hour. Hours worked = Total ÷ Rate = 252 ÷ 31.50 = 8 hours.

(c) 6 hours

Solution: Electrician’s total = $224. From the image, this matches 6 hours work (as 224 ÷ 6 ≈ 37.33/hour).

(d) 35 : 36 : 32

Solution: Payments are $245 (painter), $252 (plumber), $224 (electrician). Divide all by 7: 245÷7=35, 252÷7=36, 224÷7=32.
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