Home / iGCSE Mathematics (0580) :E2.2 Manipulate directed numbers.iGCSE Style Questions Paper 4

iGCSE Mathematics (0580) :E2.2 Manipulate directed numbers.iGCSE Style Questions Paper 4

Question

(a) Expand and simplify.

\( 4(2x-1)-6(3-x) \)

(b) Factorise completely.

(i) \( 6x^2y+9xy \)

(ii) \( 4x^2-y^2+8x+4y \)

(c) Antonio travels 100 km at an average speed of x km/h.
He then travels a further 150 km at an average speed of (x + 10) km/h.
The time taken for the whole journey is 4 hours 20 minutes.

(i) Show that \( 13x^2 – 620x – 3000 = 0 \).

(ii) Solve \( 13x^2 – 620x – 3000 = 0 \) to find the speed Antonio travels for the first 100 km of the journey.
You must show all your working and give your answer correct to 1 decimal place.

▶️ Answer/Explanation
Solution

(a) \(14x – 22\) or \(2(7x – 11)\)

First expand both brackets: \(8x – 4 – 18 + 6x\). Then combine like terms to get \(14x – 22\).

(b)(i) \(3xy(2x + 3)\)

Factor out the greatest common factor \(3xy\) from both terms to get the simplified form.

(b)(ii) \((2x + y)(2x – y + 4)\)

Group terms: \((4x^2 – y^2) + (8x + 4y)\). Factor difference of squares first, then common factor in second group.

(c)(i) Proof shown

\[ \frac{100}{x} + \frac{150}{x+10} = 4\frac{1}{3} \]

Combine fractions: \[ \frac{100(x+10)+150x}{x(x+10)} = \frac{13}{3} \]

Simplify numerator: \[ \frac{250x+1000}{x(x+10)} = \frac{13}{3} \]

Cross multiply and expand: \[ 750x + 3000 = 13x^2 + 130x \]

Rearrange terms: \[ 13x^2 – 620x – 3000 = 0 \]

(c)(ii) 52.1 km/h

Use quadratic formula with \(a=13\), \(b=-620\), \(c=-3000\). Calculate discriminant and find positive root, rounding to one decimal place.

Question

(a) Expand and simplify

(2p² – 3)(3p² – 2)

(b) s = ½(u + ν)t

(i) Find the value of s when u = 20, ν = 30 and t = 7

(ii) Rearrange the formula to write ν in terms of s, u and t

(c) Factorise completely.

(i) 2qt – 3t – 6 + 4q

(ii) x³ – 25x

▶️ Answer/Explanation
Solution

(a) 6p⁴ – 13p² + 6

Multiply each term: (2p²×3p²) + (2p²×-2) + (-3×3p²) + (-3×-2) = 6p⁴ – 4p² – 9p² + 6. Combine like terms.

(b)(i) 175

Substitute values: s = ½(20+30)×7 = ½×50×7 = 25×7 = 175.

(b)(ii) ν = (2s – ut)/t

Multiply both sides by 2: 2s = (u+ν)t. Expand: 2s = ut + νt. Isolate ν: ν = (2s – ut)/t.

(c)(i) (2q – 3)(t + 2)

Group terms: (2qt + 4q) + (-3t – 6). Factor each group: 2q(t+2) -3(t+2). Common factor (t+2).

(c)(ii) x(x + 5)(x – 5)

Factor out x: x(x² – 25). Recognize difference of squares: x² – 25 = (x+5)(x-5).

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