Home / iGCSE Mathematics (0580) :E2.6 Represent inequalities graphically and use this representation to solve simple linear programming problems.iGCSE Style Questions Paper 4

iGCSE Mathematics (0580) :E2.6 Represent inequalities graphically and use this representation to solve simple linear programming problems.iGCSE Style Questions Paper 4

Question

A company makes scientific calculators and graphic calculators.
Each day they make x scientific calculators and y graphic calculators.

These inequalities describe the number of scientific and graphic calculators they make each day:

$x < 180$     $y \leq 90$     $x + y \leq 240$

(a) Complete these two statements:

The company makes fewer than …… scientific calculators each day.

The company can make a maximum of ….. calculators each day.

(b) Scientific calculators cost \($12\) to make.
Graphic calculators cost \($18\) to make.
Each day the company spends at least \($2700\) making calculators.

Show that $2x + 3y \geq 450$.

(c) The region R satisfies these four inequalities:

$x < 180$,   $y \leq 90$,   $x + y \leq 240$,   $2x + 3y \geq 450$

By drawing four suitable lines and shading unwanted regions, find and label the region R.

(d) Scientific calculators are sold for a profit of \($10\).
Graphic calculators are sold for a profit of \($30\).

Calculate the maximum profit made by the company in one day.

▶️ Answer/Explanation
Solution

(a) 180 and 240

The first blank comes from the inequality x ≤ 180. The second blank is the maximum total calculators from x + y ≤ 240.

(b) Total cost is 12x + 18y ≥ 2700. Dividing all terms by 6 gives 2x + 3y ≥ 450.

(c) The region R is where all four inequalities are satisfied simultaneously. This involves drawing all four boundary lines and shading the appropriate areas.

(d) \$4200

The maximum profit occurs at the vertex (150, 90). Profit = 10×150 + 30×90 = 1500 + 2700 = \$4200.

Question

(a) 

Write down the inequality shown by the number line.

(b) -3 ≤ 2x + 3 < 9

(i) Solve the inequality.

(ii) Write down all the integer values of x that satisfy the inequality.

(c) Solve the equations.

(i) \( 3(3-x) – \frac{2(x+2)}{5} = 1 \)

(ii) \( \frac{5}{x+3} = \frac{3}{x+5} \)

▶️ Answer/Explanation
Solution

(a) -2 < x ≤ 4

The open circle at -2 means x > -2, and the closed circle at 4 means x ≤ 4.

(b)(i) -3 ≤ x < 3

Subtract 3 from all parts: -6 ≤ 2x < 6. Then divide by 2: -3 ≤ x < 3.

(b)(ii) -3, -2, -1, 0, 1, 2

These are all integers between -3 (included) and 3 (not included).

(c)(i) x = 2

Multiply all terms by 5: 45-15x – 2x-4 = 5. Combine like terms: 41-17x = 5.

Then -17x = -36 → x = 36/17 ≈ 2.117 (exact form).

(c)(ii) x = -8

Cross-multiply: 5(x+5) = 3(x+3). Expand: 5x+25 = 3x+9.

Subtract 3x: 2x+25 = 9. Subtract 25: 2x = -16 → x = -8.

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