Each side is painted red, blue, green, yellow or orange. The table shows some of the probabilities of the spinner landing on each colour.
(a) Complete the table. (b) Dan spins the spinner once. Find the probability that the spinner lands on red or blue.
▶️ Answer/Explanation
Solution
(a) Ans: 0.11
The sum of all probabilities must be 1. Given probabilities for red, blue, green, and yellow sum to $0.3 + 0.16 + 0.18 + 0.25 = 0.89$. Thus, the remaining probability for orange is $1 – 0.89 = 0.11$.
(b) Ans: 0.46
To find the probability of landing on red or blue, add their individual probabilities: $P(\text{Red}) + P(\text{Blue}) = 0.3 + 0.16 = 0.46$.
Question
A spinner is spun. The possible outcomes are A, B, C or D. The probability of spinning A, C or D is shown in the table.
Complete the table.
▶️ Answer/Explanation
Solution
Ans: 0.4
The sum of all probabilities must be equal to $1$.
Given probabilities: $P(A) = 0.2$, $P(C) = 0.05$, and $P(D) = 0.35$.
Let $P(B) = x$. Then, $0.2 + x + 0.05 + 0.35 = 1$.
