Home / IGCSE Physics (0625) 1.5.2 Turning effect Paper 4

IGCSE Physics (0625) 1.5.2 Turning effect Paper 4

Question

(a) State the name that is given to the turning effect of a force.

…………………………………………………………………………………………………………………….. [1]

   (b) A gate has rusty hinges that are very stiff. A man opens the gate by pulling on it, as shown in Fig. 1.1.

After he has passed through the opening, he closes the gate behind him.

When closing the gate, the man pulls it at a point halfway along its length.

State two differences between his force when closing the gate and his force when

he opened the gate.

1. ……………………………………………………………………………………………………………………..

2. ……………………………………………………………………………………………………………………..[2]

(c) Suggest one way of reducing the force needed to open the gate.

…………………………………………………………………………………………………………………….. [1]                [Total: 4]

Answer/Explanation

Ans: (a) moment/torque ignore turning force 

(b) opposite direction  condone different direction(s) larger or correct reverse argument (opening force is smaller) 

(c) (apply) force further from hinge OR oil/reduce friction/new hinge/use an assist mechanism/replace hinge(s)

Question

(a) An object is moving in a straight line at constant speed.
State three ways in which a force may change the motion of the object.

1 ……………………………………………………………………………………………………………………………..
2 ……………………………………………………………………………………………………………………………..
3 ……………………………………………………………………………………………………………………………..

(b) Fig. 3.1 shows an object suspended from two ropes. The weight of the object is 360 N. The magnitude of the tension in each rope is T.

 

In the space below, determine the tension T by drawing a vector diagram of the forces acting on the object.

State the scale you have used.
scale …………………………………………………………………………………………..
T = …………………………………………………………………………………………..

Answer/Explanation

Answer:
(a) Accelerate or increase speed OR Decelerate or decrease speed OR Change speed 
Change direction OR causes rotation

(b) Sensible scale stated
T vectors, labelled T or with arrow, both of same length, drawn at right angles (any orientation)
Triangle or parallelogram completed using candidate’s T vectors 
Correct orientation vector diagram with 360N vector vertical
T value stated: 250 or 260N

Question

(a) Complete the statement by writing in the blank spaces.
The moment of a force about a pivot is equal to …………………………………………………………….
multiplied by …………………………………………………………………………………………….

(b) Fig. 3.1 shows a horizontal rod of length 2.4 m and weight 160 N. The weight of the rod acts at its centre. The rod is suspended by two vertical ropes X and Y. The tension in each rope is 80 N.

                           

(i) State the name given to the point at which the weight of the rod acts.
……………………………………………………………………………………………………………………..

(ii) Calculate the mass of the rod.
mass =………………………………………………

(iii) The rod is in equilibrium.
Using data from Fig. 3.1, explain why.
..………………………………………………………………………………………………………………………..
………………………………………………………………………………………………………………………….
………………………………………………………………………………………………………………………….
………………………………………………………………………………………………………………………….
………………………………………………………………………………………………………………………….
……………………………………………………………………………………………………………………..

Answer/Explanation

Answer:
(a) ..(the) force× its perpendicular distance from pivot / a point

(b)(i) centre of mass
(ii) (mass =) 160 / 10 = 16 kg
(iii) (Not moving up or down because) no resultant (vertical) force
OR upward force = downward force
80 N + 80 N = 160 N
(Not rotating because) no resultant moment (about any point)
OR (sum of) clockwise moments = (sum of) anticlockwise moments
C1clockwise moment (about centre) = 80× 1.2
anticlockwise moment (about centre) = 80 × 1.2

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