Home / iGCSE Physics (0625) 2.1.3 Gases and the absolute scale of temperature Paper 4 -Exam Style Questions

iGCSE Physics (0625) 2.1.3 Gases and the absolute scale of temperature Paper 4 -Exam Style Questions- New Syllabus

Question

(a) Table 10.1 shows data for planets A, B, C and D.
(i) State and explain which one of these planets is closest to the Sun.
(ii) Calculate the surface temperature of planet D in $^\circ\text{C}$.
(iii) An object falls through a height of $2\text{ m}$ on each of the planets in Table 10.1. State and explain on which planet the object falls $2\text{ m}$ in the shortest time. Ignore any effect due to the atmosphere.
(b) Fig. 10.1 shows some of the stages in the life cycle of a massive star.
(i) Complete Fig. 10.1 by adding the correct terms.
(ii) State the quantity that the brightness of a supernova in a galaxy can be used to determine.

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

• Topic $6.1.2$ — The Solar System (Part $\mathrm{a(i)}$)
• Topic $2.1 .3$ — Gases and the absolute scale of temperature (Part $\mathrm{a(ii)}$)
• Topic $1.3$ — Mass and weight (Part $\mathrm{a(iii)}$)
• Topic $6.2.2$ — Stars (Part $\mathrm{b(i)}$)
• Topic $6.2.3$ — The Universe (Part $\mathrm{b(ii)}$)

▶️ Answer/Explanation
Part (a)(i)

Correct Answer: Planet B

Detailed solution: Planet B is the closest to the Sun because it has the highest surface temperature ($623\text{ K}$). In a solar system, planets closer to the central star receive more intense radiation per unit area, generally leading to higher surface temperatures compared to planets further away.

Part (a)(ii)

Correct Answer: $-180 ^\circ\text{C}$

Detailed solution: To convert from Kelvin ($\text{K}$) to degrees Celsius ($^\circ\text{C}$), use the formula $T(\text{in K}) = \theta(\text{in } ^\circ\text{C}) + 273$. Rearranging for Celsius gives $\theta = T – 273$. For planet D, the calculation is $93 – 273 = -180 ^\circ\text{C}$.

Part (a)(iii)

Correct Answer: Planet A

Detailed solution: The time taken to fall a fixed height is inversely related to the acceleration due to gravity ($g$). Planet A has the highest gravitational field strength ($23.0\text{ N/kg}$), which is equivalent to the highest acceleration of free fall. A greater acceleration results in a faster increase in velocity, meaning the object covers the $2\text{ m}$ distance in the shortest time.

Part (b)(i)

Correct Answer: Red supergiant; (new) heavier elements; neutron star OR black hole.

Detailed solution: A massive star expands to form a red supergiant. When it explodes as a supernova, it forms a nebula containing hydrogen and new heavier elements. The collapse of the remaining core leaves behind either a neutron star or a black hole, depending on the initial mass of the star.

Part (b)(ii)

Correct Answer: Distance (from Earth) to the galaxy.

Detailed solution: Supernovae have a known peak luminosity (intrinsic brightness). By measuring the apparent brightness observed from Earth and comparing it to this known intrinsic brightness, astronomers can calculate the distance $d$ to the galaxy in which the supernova occurred.

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