Home / iGCSE Physics (0625) 2.3.4 Consequences of energy transfer Paper 4 -Exam Style Questions

iGCSE Physics (0625) 2.3.4 Consequences of energy transfer Paper 4 -Exam Style Questions- New Syllabus

Question

(a) Fig. 5.1 shows an electric heater used to heat a room.
The dimensions of the room are 4.5m×6.1m×2.4m. The density of air is 1.2kg/m 3 .
(i) Show that the mass of air in the room is 79kg.
(ii) The power of the heater is 1100W. The specific heat capacity of air is 1000J/(kg ∘ C). Calculate the time taken to increase the temperature of the air in the room from 16.0 ∘ C to 20.0 ∘ C.
(iii) Suggest one reason why the time calculated in (a)(ii) is the minimum time needed to increase the temperature of the air in the room from 16.0 ∘ C to 20.0 ∘ C.
(b) Fig. 5.2 shows a cross-section of a double-glazed window in the room.
State the main methods of thermal energy transfer from the room to outside which are reduced by this type of window.

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

• Topic 1.4 — Density (Part (a)(i))

• Topic 2.2.2 — Specific heat capacity (Part (a)(ii))

• Topic 2.3.4 — Consequences of thermal energy transfer (Parts (a)(iii), (b))

▶️ Answer/Explanation

(a)(i)
For the correct answer:
79kg

To find the mass, first calculate the room’s volume using V=length×width×height=4.5×6.1×2.4=65.88m 3 . Using the density formula ρ= V m ​ , rearrange it to m=ρ×V. Substituting the values, m=1.2kg/m 3 ×65.88m 3 =79.056kg, which rounds to 79kg as required.

(a)(ii)
For the correct answer:
290s

First, calculate the thermal energy required using ΔE=mcΔθ=79×1000×(20.0−16.0)=316,000J. Since power is the rate of energy transfer, use the equation P= t ΔE ​ rearranged to t= P ΔE ​ . The time taken is t= 1100W 316,000J ​ ≈287.3s, which rounds to 290s to two significant figures.

(a)(iii)
For the correct answer:
thermal energy is lost from the room (to the surroundings)

The calculation assumes all energy from the heater goes into the air, but in reality, thermal energy is lost through walls and windows via conduction and convection. Additionally, some energy is used to heat the objects and furniture within the room rather than just the air itself. Consequently, the actual time taken would be longer than this theoretical minimum.

(b)
For the correct answer:
conduction AND convection

Double glazing uses a trapped layer of air or a vacuum between two glass panes to reduce heat loss. Air is a very poor thermal conductor, which significantly limits heat transfer by conduction. Furthermore, because the gap is narrow and sealed, air cannot circulate freely to form large convection currents, thereby minimizing thermal energy transfer by convection to the outside.

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