iGCSE Physics (0625) 4.2.4 Resistance Paper 3 -Exam Style Questions- New Syllabus
Question

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):
• Topic 4.2.4 — Resistance (Part (b))
• Topic 4.2.5 — Electrical energy and electrical power (Part (c))
• Topic 4.3.1 — Circuit diagrams and circuit components (Part (a))
▶️ Answer/Explanation
(a)
For the correct answer:
correct symbol voltmeter in parallel with lamp
A voltmeter must be connected in parallel with the component across which the potential difference is being measured. The symbol for a voltmeter is a circle with a ‘V’ inside, and it should be drawn with leads connected to the two terminals of the lamp.
(b)
For the correct answer:
$29\ \Omega$
The resistance is calculated using the equation $R = \frac{V}{I}$. Substituting the given values, $R = \frac{12\text{ V}}{0.41\text{ A}}$, which yields approximately $29.3\ \Omega$. Rounded to two significant figures to match the precision of the given current, the result is $29\ \Omega$.
(c)
For the correct answer:
$4.9\ \text{W}$
Electrical power is calculated using $P = I \times V$. Substituting the values, $P = 0.41\text{ A} \times 12\text{ V} = 4.92\text{ W}$. Rounded to two significant figures, the power transferred is $4.9\text{ W}$.
