Home / iGCSE Physics (0625) 4.5.3 The magnetic effect of a current Paper 3 -Exam Style Questions- New Syllabus

iGCSE Physics (0625) 4.5.3 The magnetic effect of a current Paper 3 -Exam Style Questions- New Syllabus

Question

Fig. 8.1 shows an arrangement for making an electromagnet. The electromagnet consists of a solenoid and a core.
(a) (i) The electromagnet is a temporary magnet.
State one material which is suitable for the core of the electromagnet.
(ii) The battery is made from cells connected in series. Each cell in the battery has an electromotive force (e.m.f.) of $1.5$ V.
Calculate the number of cells in the battery in Fig. 8.1.
(b) The switch is closed. The direction of the current in the solenoid is shown in Fig. 8.1.
(i) There is a magnetic field around the electromagnet.
State the name of a piece of equipment that can show the direction of a magnetic field.
(ii) State the name of the pole labelled X on the core of the electromagnet.
(c) The resistance of the solenoid is $8.0$ Ω.
The current in the solenoid is $1.2$ A.
Calculate the potential difference (p.d.) across the solenoid.

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

Topic 4.1 — Simple phenomena of magnetism (Parts (a)(i), (b)(i))
Topic 4.3.2 — Series and parallel circuits (Part (a)(ii))
Topic 4.5.3 — Magnetic effect of a current (Part (b)(ii))
Topic 4.2.4 — Resistance (Part (c))

▶️ Answer/Explanation

(a) (i)
For the correct answer:
(soft) iron

An electromagnet requires a core that can be easily magnetized and demagnetized (a temporary magnetic material). Soft iron is the standard material used for this purpose because it loses its induced magnetism almost instantly when the electrical current is switched off.

(a) (ii)
For the correct answer:
$8$ (cells)

The total electromotive force (e.m.f.) of cells connected in series is equal to the sum of their individual e.m.f. values. To find the total number of cells, you divide the total battery e.m.f. ($12$ V) by the e.m.f. of a single cell ($1.5$ V). Using the calculation $12 \div 1.5 = 8$, we find that there are $8$ cells in the circuit.

(b) (i)
For the correct answer:
(plotting) compass

A plotting compass contains a small magnetic dipole that aligns itself with the local magnetic field. By placing it at various positions around the electromagnet, the north pole of the compass needle will point in the direction of the magnetic field lines, allowing the field pattern to be visualized.

(b) (ii)
For the correct answer:
North OR N (pole)

The polarity of an electromagnet can be determined using the right-hand grip rule. If you wrap the fingers of your right hand around the solenoid in the direction of the current (which points downwards on the visible front coils), your thumb points to the right. Therefore, the right end (labelled X) is the North pole.

(c)
For the correct calculated value:
$9.6$ V

The potential difference across a component can be calculated using the resistance equation, which can be rearranged to $V = I \times R$. Given the current $I = 1.2$ A and the resistance $R = 8.0$ Ω, you substitute these values into the formula to get $V = 1.2 \times 8.0$. This yields a potential difference of $9.6$ V.

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