Home / iGCSE Physics (0625) 5.1.1 The atom Paper 4 -Exam Style Questions

iGCSE Physics (0625) 5.1.1 The atom Paper 4 -Exam Style Questions- New Syllabus

Question

(a) Alpha (α) particles are directed at a very thin sheet of gold foil. The following observations provide evidence for the nuclear model of the atom. State what conclusions may be made about the model of the atom from these observations.
(i) Observation: most of the particles pass straight through the foil.
(ii) Observation: a few particles bounce back or are deflected through large angles.
(b) Fig. 8.1 shows three beams of ionising radiation, alpha, beta and gamma, passing between two parallel plates. The plates are charged and there is a uniform electric field between them.
(i) State and explain which path P, Q or R shows a beam of alpha particles.
(ii) State and explain the direction of the electric field between the plates.
(c) Curium-242 is a radioactive isotope. It emits alpha particles. It has a half-life of 160 days. After 480 days, the mass of curium-242 in a sample is $2.4 \times 10^{-3}\text{ g}$. Calculate the initial mass of curium-242 in the sample.

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

• Topic $5.1.1$ — The atom (Part $\mathrm{(a)}$)
• Topic $5.2.2$ — The three types of nuclear emission (Part $\mathrm{(b)}$)
• Topic $5.2.4$ — Half-life (Part $\mathrm{(c)}$)

▶️ Answer/Explanation
Part (a)

Correct Answer: (i) Most of the atom is empty space. (ii) The nucleus is positively charged / concentrated mass.

Detailed solution: (i) Since the majority of α particles pass through without any deflection, it implies they do not encounter any obstacles, concluding that the atom is mostly empty space. (ii) Large-angle deflections occur when the positive α particles come close to a concentrated positive center. This confirms the existence of a small, dense, positively charged nucleus containing most of the atom’s mass.

Part (b)

Correct Answer: (i) Path P. (ii) Direction: Upwards.

Detailed solution: (i) Path P represents alpha particles because they are much more massive than beta particles (Path R), resulting in a smaller deflection for the same field strength. (ii) The electric field is directed upwards from the positive plate to the negative plate. Alpha particles are positively charged and thus experience a force in the direction of the field, causing them to curve toward the top (negative) plate.

Part (c)

Correct Answer: $1.9 \times 10^{-2}\text{ g}$

Detailed solution: First, determine the number of half-lives: $n = \frac{480}{160} = 3$ half-lives. To find the initial mass, we multiply the final mass by $2^n$, which is $2^3 = 8$. Calculating the initial mass: $M_0 = 2.4 \times 10^{-3}\text{ g} \times 8 = 19.2 \times 10^{-3}\text{ g}$. This is expressed in standard form as $1.92 \times 10^{-2}\text{ g}$, rounded to $1.9 \times 10^{-2}\text{ g}$ for two significant figures.

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