iGCSE Physics (0625) 1.7.4 Power-Exam Style Questions- New Syllabus

Detailed solution:

The energy transferred by the heater is given by $\Delta E = P \times t$, where $P$ is power and $t$ is time.
Specific heat capacity $c$ is defined by the thermal energy equation $\Delta E = mc\Delta \theta$.
By substituting the expression for energy, we get $Pt = mc\Delta \theta$.
Rearranging this formula to make $c$ the subject gives $c = \frac{Pt}{m\Delta \theta}$.
This matches the expression provided in Option B.