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iGCSE Physics (0625) 3.4 Sound-Exam Style Questions- New Syllabus

Question

A student makes a sound in front of a large wall.
She hears an echo at time $t$ after making the sound.
The speed of sound in air is $v$.
Which expression is used to calculate the distance between the student and the wall?
A. $v \times t$
B. $v \div t$
C. $(v \times t) \div 2$
D. $(v \div t) \div 2$
▶️ Answer/Explanation
Correct Option: C

Detailed solution:

An echo is the reflection of sound. To hear an echo, the sound must travel from the student to the wall and back again.
If the distance to the wall is $d$, the total distance travelled by the sound is $2d$.
Using the formula for speed, $v = \frac{\text{total distance}}{\text{time}}$, we have $v = \frac{2d}{t}$.
Rearranging to find the distance between the student and the wall: $2d = v \times t$.
Therefore, $d = \frac{v \times t}{2}$, which is expressed as $(v \times t) \div 2$.
This matches Option C.

Question

Sound travels through air as a series of compressions and rarefactions. Which statement correctly compares a compression with a rarefaction?
A. In a compression, the wavelength is longer than in a rarefaction.
B. In a compression, the wavelength is shorter than in a rarefaction.
C. In a compression, the density of the air is greater than in a rarefaction.
D. In a compression, the density of the air is lower than in a rarefaction.
▶️ Answer/Explanation
Correct Option: C

Detailed solution:

Sound is a longitudinal wave consisting of oscillations in the medium’s pressure and density.
A compression is a region where the particles are pushed closer together, resulting in high pressure and a higher density ($\rho$).
Conversely, a rarefaction is a region where the particles are spread further apart, leading to low pressure and a lower density.
Wavelength ($\lambda$) is defined as the distance between two successive compressions or rarefactions, not a property of a single region.
Thus, the density of air is greater in a compression than in a rarefaction, making option C the correct choice.

Question
Both the amplitude and the frequency of a sound wave decrease.
What happens to the sound that is heard?
A. The sound is louder and has a higher pitch.
B. The sound is louder and has a lower pitch.
C. The sound is quieter and has a higher pitch.
D. The sound is quieter and has a lower pitch.
▶️ Answer/Explanation
Correct Option: D

Detailed solution:

The loudness of a sound wave is determined by its amplitude; a decrease in amplitude results in a quieter sound.
The pitch of a sound is determined by its frequency, where f= T 1 .
When the frequency decreases, the number of vibrations per second is lower, resulting in a lower pitch.
Since the question states both properties decrease, the sound becomes both quieter and lower in pitch.
This corresponds exactly to the description provided in Option D.
Therefore, the observed change is a quieter sound with a lower pitch.

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