Preparation of salts- CIE iGCSE Chemistry Notes - New Syllabus
Preparation of salts for iGCSE Chemistry Notes
Core Syllabus
- Describe the preparation, separation and purification of soluble salts by reaction of an acid with:
(a) an alkali by titration
(b) excess metal
(c) excess insoluble base
(d) excess insoluble carbonate - Describe the general solubility rules for salts:
(a) sodium, potassium and ammonium salts are soluble
(b) nitrates are soluble
(c) chlorides are soluble, except lead and silver
(d) sulfates are soluble, except barium, calcium and lead
(e) carbonates are insoluble, except sodium, potassium and ammonium
(f) hydroxides are insoluble, except sodium, potassium, ammonium and calcium (partially) - Define a hydrated substance as a substance that is chemically combined with water and an anhydrous substance as a substance containing no water
Supplement Syllabus
- Describe the preparation of insoluble salts by precipitation
- Define the term water of crystallisation as the water molecules present in hydrated crystals, including CuSO₄·5H₂O and CoCl₂·6H₂O
Preparation of Salts
Preparation, Separation and Purification of Soluble Salts by Reaction of an Acid with:
(a) An Alkali – by Titration
This method is used when both the acid and the base (alkali) are soluble. It involves accurately measuring and mixing the acid and alkali to obtain a neutral solution, which can be crystallised to give the salt.
- Use a pipette to add 25 cm³ of alkali to a conical flask.
- Add a few drops of indicator (e.g. phenolphthalein or methyl orange).
- Fill a burette with the acid.
- Slowly add the acid while swirling the flask until the indicator shows neutralisation.
- Repeat the titration to get consistent results (concordant readings).
- Repeat the titration without indicator using the average volume of acid.
- Evaporate the resulting salt solution and crystallise to obtain pure, dry crystals.
Example Equation:
\( \text{NaOH (aq)} + \text{HCl (aq)} \rightarrow \text{NaCl (aq)} + \text{H}_2\text{O (l)} \)
Example
Describe how to prepare a pure, dry sample of sodium sulfate crystals using sulfuric acid and sodium hydroxide.
▶️Answer/Explanation
Perform a titration with phenolphthalein to determine the volume of sulfuric acid required to neutralise sodium hydroxide. Then repeat without indicator. Evaporate the neutral solution to form crystals. Filter and dry.
Equation: \( 2\text{NaOH} + \text{H}_2\text{SO}_4 \rightarrow \text{Na}_2\text{SO}_4 + 2\text{H}_2\text{O} \)
(b) Excess Metal
This method is suitable for preparing salts of reactive metals (e.g. magnesium, zinc). The metal must be more reactive than hydrogen. It is added in excess to ensure complete reaction and then removed by filtration.
- Add excess metal (e.g. magnesium) to dilute acid (e.g. sulfuric acid).
- Allow the reaction to finish (bubbling stops).
- Filter off the unreacted metal.
- Evaporate the filtrate to crystallise the salt.
- Filter and dry the salt crystals.
Example Equation:
\( \text{Mg (s)} + \text{H}_2\text{SO}_4 (aq) \rightarrow \text{MgSO}_4 (aq) + \text{H}_2 (g) \)
Example
How would you prepare magnesium sulfate crystals using magnesium metal and sulfuric acid?
▶️Answer/Explanation
Add excess magnesium to dilute sulfuric acid. Wait until bubbling (hydrogen) stops. Filter to remove unreacted magnesium. Evaporate the filtrate and dry the crystals.
Equation: \( \text{Mg} + \text{H}_2\text{SO}_4 \rightarrow \text{MgSO}_4 + \text{H}_2 \)
(c) Excess Insoluble Base
This method is used when the base is insoluble (e.g. copper(II) oxide). It is added in excess to ensure all the acid is neutralised.
- Warm dilute acid gently in a beaker.
- Add the insoluble base a little at a time with stirring.
- Continue until no more base dissolves (excess remains).
- Filter off the unreacted base.
- Evaporate the solution to obtain salt crystals.
- Filter and dry the crystals.
Example Equation:
\( \text{CuO (s)} + \text{H}_2\text{SO}_4 (aq) \rightarrow \text{CuSO}_4 (aq) + \text{H}_2\text{O (l)} \)
Example
Describe the preparation of copper(II) sulfate crystals using copper(II) oxide and dilute sulfuric acid.
▶️Answer/Explanation
Warm sulfuric acid and add copper(II) oxide until no more dissolves. Filter off the excess solid. Evaporate the solution and allow crystals to form. Filter and dry them.
Equation: \( \text{CuO} + \text{H}_2\text{SO}_4 \rightarrow \text{CuSO}_4 + \text{H}_2\text{O} \)
(d) Excess Insoluble Carbonate
This method is used for metal carbonates such as calcium carbonate. The reaction gives off carbon dioxide gas.
- Warm dilute acid in a beaker.
- Add the insoluble carbonate gradually while stirring.
- Continue until no more bubbles are seen (reaction is complete).
- Filter to remove excess carbonate.
- Evaporate the filtrate to crystallise the salt.
- Filter and dry the crystals.
Example Equation:
\( \text{CaCO}_3 (s) + 2\text{HCl} (aq) \rightarrow \text{CaCl}_2 (aq) + \text{CO}_2 (g) + \text{H}_2\text{O (l)} \)
Example
How would you make calcium chloride crystals using calcium carbonate and dilute hydrochloric acid?
▶️Answer/Explanation
Add calcium carbonate to warm dilute hydrochloric acid until bubbling (CO₂) stops. Filter the excess solid. Evaporate the solution to form crystals. Filter and dry them.
Equation: \( \text{CaCO}_3 + 2\text{HCl} \rightarrow \text{CaCl}_2 + \text{CO}_2 + \text{H}_2\text{O} \)
Preparation of insoluble salts by precipitation
Precipitation is a method used to prepare insoluble salts by mixing two aqueous solutions. When the ions from the solutions react, an insoluble solid (called a precipitate) forms and can be filtered out.
Key steps:
- Select two soluble salts such that one provides the desired cation and the other provides the desired anion.
- Mix the solutions — the insoluble salt will precipitate out.
- Filter the mixture to separate the solid precipitate.
- Wash the precipitate with distilled water to remove soluble impurities.
- Dry the solid between filter papers or in a warm oven.
Why this works: You are using a double displacement (ionic exchange) reaction where the product is an insoluble salt.
Common examples of insoluble salts:
- Silver chloride – \( \text{AgCl} \)
- Lead(II) sulfate – \( \text{PbSO}_4 \)
- Barium sulfate – \( \text{BaSO}_4 \)
Example
Describe how to prepare a pure, dry sample of barium sulfate (BaSO₄).
▶️Answer/Explanation
Mix aqueous solutions of barium nitrate and sulfuric acid:
\( \text{Ba(NO}_3)_2 (aq) + \text{H}_2\text{SO}_4 (aq) \rightarrow \text{BaSO}_4 (s) + 2\text{HNO}_3 (aq) \)
Barium sulfate precipitates out as an insoluble white solid. Filter the mixture to collect the solid. Wash with distilled water. Dry it using filter paper or in a warm oven.
Example
How would you prepare silver chloride (AgCl) crystals in the lab?
▶️Answer/Explanation
Mix aqueous solutions of silver nitrate and sodium chloride:
\( \text{AgNO}_3 (aq) + \text{NaCl} (aq) \rightarrow \text{AgCl} (s) + \text{NaNO}_3 (aq) \)
Silver chloride appears as a white precipitate. Filter, wash with distilled water to remove soluble salts, then dry the AgCl between filter papers.
Solubility Rules for Salts
Solubility Rules for Salts
Understanding solubility is crucial in salt preparation. It determines which method to use—whether a salt can be made by titration, reaction with excess base, or precipitation. Below are the general solubility rules you must know:
(a) All sodium, potassium, and ammonium salts are soluble
These salts are always soluble in water regardless of the anion. Examples:
- \( \text{NaCl} \) – sodium chloride
- \( \text{KNO}_3 \) – potassium nitrate
- \( \text{(NH}_4)_2\text{SO}_4 \) – ammonium sulfate
(b) All nitrates are soluble
No exceptions. Every nitrate salt dissolves easily in water. Examples:
- \( \text{Cu(NO}_3)_2 \) – copper(II) nitrate
- \( \text{Mg(NO}_3)_2 \) – magnesium nitrate
(c) Most chlorides are soluble
Examples of soluble chlorides include:
- \( \text{NaCl} \), \( \text{KCl} \), \( \text{FeCl}_3 \)
Exceptions (insoluble chlorides):
- \( \text{AgCl} \) – silver chloride
- \( \text{PbCl}_2 \) – lead(II) chloride (only slightly soluble in hot water)
(d) Most sulfates are soluble
Common examples include:
- \( \text{Na}_2\text{SO}_4 \), \( \text{CuSO}_4 \), \( \text{K}_2\text{SO}_4 \)
Exceptions (insoluble or slightly soluble):
- \( \text{BaSO}_4 \) – barium sulfate
- \( \text{PbSO}_4 \) – lead(II) sulfate
- \( \text{CaSO}_4 \) – calcium sulfate (sparingly soluble)
(e) Most carbonates are insoluble
Most carbonate salts do not dissolve in water and form precipitates. Examples of insoluble carbonates:
- \( \text{CaCO}_3 \), \( \text{CuCO}_3 \), \( \text{FeCO}_3 \)
Exceptions (soluble carbonates):
- \( \text{Na}_2\text{CO}_3 \), \( \text{K}_2\text{CO}_3 \), \( \text{(NH}_4)_2\text{CO}_3 \)
(f) Most hydroxides are insoluble
Examples of insoluble hydroxides:
- \( \text{Fe(OH)}_3 \), \( \text{Cu(OH)}_2 \), \( \text{Al(OH)}_3 \)
Exceptions (soluble hydroxides):
- \( \text{NaOH} \), \( \text{KOH} \), \( \text{NH}_4\text{OH} \)
- \( \text{Ca(OH)}_2 \) is only slightly soluble – forms limewater
Example
Which of the following salts is insoluble in water?
A. \( \text{KNO}_3 \)
B. \( \text{AgCl} \)
C. \( \text{Na}_2\text{SO}_4 \)
D. \( \text{(NH}_4)_2\text{CO}_3 \)
▶️Answer/Explanation
Answer: B. \( \text{AgCl} \)
\( \text{KNO}_3 \): Soluble – all potassium and nitrate salts are soluble
\( \text{Na}_2\text{SO}_4 \): Soluble – all sodium salts and most sulfates are soluble
\( \text{(NH}_4)_2\text{CO}_3 \): Soluble – ammonium carbonates are exceptions
\( \text{AgCl} \): Insoluble – one of the few insoluble chlorides
Example
Why can’t copper(II) carbonate be prepared by reacting an acid with copper(II) hydroxide?
▶️Answer/Explanation
Because copper(II) carbonate is insoluble in water, it cannot be prepared by neutralising a soluble base (like copper(II) hydroxide) with an acid and crystallising the salt. Instead, it is made by a precipitation reaction between two soluble solutions, e.g., copper(II) sulfate and sodium carbonate.
Hydrated and Anhydrous Substances
Hydrated and Anhydrous Substances
Hydrated substances are compounds that include a specific number of water molecules integrated into their crystal lattice. This water is not merely present physically or trapped; it is chemically bonded as part of the structure of the salt. These water molecules are called the water of crystallisation.
This bonding with water changes the appearance and physical properties of the substance. For example, many hydrated salts are brightly coloured due to the presence of water in the crystal structure.
Anhydrous substances, in contrast, contain no water molecules in their structure. An anhydrous compound can be obtained by heating the hydrated form to remove the water of crystallisation. The transition from hydrated to anhydrous is usually accompanied by a clear colour change or change in physical state.
For example:
Hydrated copper(II) sulfate is bright blue in colour, while its anhydrous form is white.
\( \text{CuSO}_4 \cdot 5\text{H}_2\text{O} \xrightarrow{\text{heat}} \text{CuSO}_4 + 5\text{H}_2\text{O} \)
This reaction shows the loss of water when hydrated copper(II) sulfate is heated to form anhydrous copper(II) sulfate.
Importance:
- Hydrated and anhydrous salts are often used in laboratories as indicators for the presence of water or moisture.
- Anhydrous copper(II) sulfate, for instance, is a common chemical used to test for water. It turns blue in the presence of water.
- Reversible hydration and dehydration are also important in the manufacturing of pharmaceuticals and food storage materials.
Example
How can you use copper(II) sulfate to test for the presence of water in a liquid sample?
▶️Answer/Explanation
Use anhydrous copper(II) sulfate, which is a white powder.
Add the liquid sample to the powder.
If water is present, the white powder will turn blue, forming hydrated copper(II) sulfate:
\( \text{CuSO}_4 + 5\text{H}_2\text{O} \rightarrow \text{CuSO}_4 \cdot 5\text{H}_2\text{O} \)
This colour change acts as a simple and effective test for water.
Water of Crystallisation
Water of crystallisation refers to the fixed number of water molecules that are chemically bonded within the crystalline structure of a salt.
These water molecules are not just physically trapped between the salt particles , they are an essential part of the salt’s chemical formula and structure. Such salts are called hydrated salts.
Each hydrated salt has a definite number of water molecules associated with each formula unit. This number is shown in the chemical formula using a dot.
Examples of hydrated salts:
- Copper(II) sulfate pentahydrate: \( \text{CuSO}_4 \cdot 5\text{H}_2\text{O} \)
- Cobalt(II) chloride hexahydrate: \( \text{CoCl}_2 \cdot 6\text{H}_2\text{O} \)
When these salts are heated, the water of crystallisation is removed as steam, and the salt becomes anhydrous.
For example:
\( \text{CuSO}_4 \cdot 5\text{H}_2\text{O} \xrightarrow{\text{heat}} \text{CuSO}_4 + 5\text{H}_2\text{O} \)
This reaction shows that 5 moles of water are lost per mole of hydrated copper(II) sulfate, leaving anhydrous copper(II) sulfate, which is white.
Importance of water of crystallisation:
- It affects the appearance, colour, and mass of a substance.
- It must be accounted for in chemical equations and calculations, especially in determining molar mass and percentage composition.
- It provides evidence of reversible physical changes involving water.
Example
Determine the number of moles of water of crystallisation in 5.00 g of hydrated copper(II) sulfate if the anhydrous salt has a mass of 3.20 g after heating.
▶️Answer/Explanation
Step 1: Find the mass of water lost.
Water lost = 5.00 g – 3.20 g = 1.80 g
Step 2: Moles of anhydrous CuSO₄ = \( \frac{3.20}{159.5} = 0.0201 \, \text{mol} \)
Step 3: Moles of water = \( \frac{1.80}{18.0} = 0.100 \, \text{mol} \)
Step 4: Mole ratio of water to salt = \( \frac{0.100}{0.0201} \approx 5 \)
Therefore, the formula is: \( \text{CuSO}_4 \cdot 5\text{H}_2\text{O} \)