CIE iGCSE Co-Ordinated Science B2.2 Size of specimens Exam Style Questions Paper 1
Question
What is the formula for magnification?
(A) $\frac{\text{actual size}}{\text{image size}}$
(B) $\frac{\text{actual size}}{\text{image size}}$× 100
(C) $\frac{\text{image size}}{\text{actual size}}$
(D) $\frac{\text{image size}}{\text{actual size}}$ mm
▶️Answer/Explanation
Ans : C
Question
The diagram shows a cell with a magnification of ×1000.
The width of the image is 45 mm.
What is the actual width of the cell?
(A) 45 mm (B) 4.5 mm (C) 0.45 mm (D) 0.045 mm
▶️Answer/Explanation
Ans : D
Question
The diagram shows a palisade cell from a leaf magnified 250.
The chloroplast labelled X measures 5 mm on the diagram.
What is its actual length?
(A) 0.25 mm
(B) 0.05 mm
(C) 0.02 mm
(D) 0.01 mm
▶️Answer/Explanation
Ans: C
Question
The diagram shows a beetle.
The length of the diagram is 75 mm.
The actual length of the beetle is 5 mm.
What is the magnification?
(A) ×5
(B) ×15
(C) ×80
(D) ×375
▶️Answer/Explanation
Ans: B
Question
A student draws a diagram of a chicken’s egg and includes the magnification, m, of the drawing.
The student writes m = $\times2$.
The image length on the diagram is 140 mm.
What is the length of the actual chicken’s egg?
(A) 35 mm
(B) 70 mm
(C) 140 mm
(D) 280 mm
▶️Answer/Explanation
Ans : B
Question
The photograph shows a bumble bee at a magnification of ×6. The line shows the length of the bumble bee. What is the actual length of the bumble bee?
A. 0.05 mm
B. 20 mm
C. 126 mm
D. 720 mm
▶️Answer/Explanation
Answer: B
Explanation: To find the actual length, divide the magnified length by the magnification factor. If the magnified length is 120 mm, then the actual length is 120 mm / 6 = 20 mm.
Question
The length of an insect in a photograph is measured as 17 mm. The actual length of the insect is 12 mm.
What is the magnification of the insect in the photograph?
A) ×1.2
B) ×1.3
C) ×1.4
D) ×1.5
▶️Answer/Explanation
Answer: C) ×1.4
Explanation: Magnification is calculated using the formula: \[ \text{Magnification} = \frac{\text{Image size}}{\text{Actual size}} \] Substituting the given values: \[ \text{Magnification} = \frac{17\, \text{mm}}{12\, \text{mm}} = 1.416 \approx 1.4 \] Therefore, the magnification is ×1.4.