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CIE iGCSE Co-Ordinated Science B2.2 Size of specimens Exam Style Questions Paper 1

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Question

The photograph shows a caterpillar. The length of line PQ is 90 mm. The actual length of the caterpillar is 30 mm.

What is the magnification of the photograph?

A. × 0.33
B. × 3.0
C. × 27
D. × 2700

▶️ Answer/Explanation
Magnification is calculated using the formula: \(\text{Magnification} = \frac{\text{image size}}{\text{actual size}}\).
The image size is 90 mm and the actual size is 30 mm. So, \(\frac{90}{30} = 3\). The photograph has a magnification of × 3.0.
✅ Answer: (B)

Question

A student draws a diagram of a chicken’s egg and includes the magnification, m, of the drawing.

The student writes m = ×2.

The image length on the diagram is 140 mm.

What is the length of the actual chicken’s egg?

A. 35 mm
B. 70 mm
C. 140 mm
D. 280 mm

▶️ Answer/Explanation
The formula for magnification is \( \text{magnification} = \dfrac{\text{image size}}{\text{actual size}} \).
Rearranging gives \( \text{actual size} = \dfrac{\text{image size}}{\text{magnification}} = \dfrac{140}{2} = 70 \) mm.
So the actual length of the chicken’s egg is 70 mm.
✅ Answer: (B)

Question

The diagram shows a beetle.

The length of the diagram is 75 mm.
The actual length of the beetle is 5 mm.
What is the magnification?

A. × 5
B. × 15
C. × 80
D. × 375

▶️ Answer/Explanation
Magnification is calculated using the formula: \(\text{Magnification} = \dfrac{\text{image size}}{\text{actual size}}\).
The image (diagram) length is 75 mm and the actual length of the beetle is 5 mm.
So, \(\dfrac{75}{5} = 15\).
✅ Answer: (B)

Question

The diagram shows a palisade cell from a leaf magnified × 250.

The chloroplast labelled X measures 5 mm on the diagram.

What is its actual length?

A. 0.25 mm
B. 0.05 mm
C. 0.02 mm
D. 0.01 mm

▶️ Answer/Explanation
Actual size is found using \( \text{actual size} = \dfrac{\text{image size}}{\text{magnification}} \).
Here, image size = 5 mm and magnification = 250.
So \( \dfrac{5}{250} = 0.02 \) mm.
✅ Answer: (C)

Question

What is the formula for magnification?

A. \( \dfrac{\text{actual size}}{\text{image size}} \)
B. \( \dfrac{\text{actual size}}{\text{image size}} \times 100 \)
C. \( \dfrac{\text{image size}}{\text{actual size}} \)
D. \( \dfrac{\text{image size}}{\text{actual size}} \) mm

▶️ Answer/Explanation
Magnification compares how much larger an image appears than the real object.
It is defined as \( \text{magnification} = \dfrac{\text{image size}}{\text{actual size}} \), a ratio with no units.
✅ Answer: (C)
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