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CIE iGCSE Co-Ordinated Science P1.2 Motion Exam Style Questions Paper 3

Question

(a) A student runs 100 m. The running track is divided into five 20 m sections. The student is timed over each 20 m section. Table 11.1 shows the results.
(i) Use Table 11.1 to calculate the average speed of the student over the 100 m run.
(ii) The average power output of the student over the final section is 600 W.
Calculate the work done by the student in 3.0 s.
State the unit of your answer.
(b)(i) After the run the student starts sweating and the student’s body cools down.
State the process responsible for this cooling down by sweating.
(ii) The student wears a black T-shirt in the Sun and becomes too hot.
        Another student wears a white T-shirt in the Sun and does not become as hot.
        Explain why.
(iii) The Sun consists mostly of two elements.
State the name of one of these elements.
(iv) Most of the energy emitted by the Sun is from three regions of the electromagnetic spectrum.
Name these three regions.

Most-appropriate topic codes (Cambridge IGCSE Coordinated Sciences 0654):

• Topic P1.2 — Motion (Part (a)(i))
• Topic P1.6.4 — Power (Part (a)(ii))
• Topic P2.2.2 — Melting, boiling and evaporation (Part (b)(i))
• Topic P2.3.3 — Radiation (Part (b)(ii))
• Topic P6.2.1 — The Sun as a star (Part (b)(iii), (b)(iv))

▶️ Answer/Explanation

(a)(i) evidence of total time = 15 (s); v = s/t (in any form) OR (average speed =) 100/15; 6.7 (m/s)
Total time = 3.7 + 3.1 + 2.6 + 2.6 + 3.0 = 15.0 s. Average speed = 100/15 = 6.7 m/s.

(a)(ii) P = W/t (in any form) OR (work done =) 600 × 3.0; 1800; J
Work done = power × time = 600 × 3.0 = 1800 J. The unit for work is the joule (J).

(b)(i) evaporation
Sweating cools the body because the most energetic water particles evaporate from the skin surface, taking thermal energy with them and lowering the skin temperature.

(b)(ii) white absorbs less (thermal) radiation / white reflects more (thermal) radiation
White surfaces reflect most incident radiation, so less thermal energy is absorbed. Black surfaces absorb more radiation, leading to greater heating.

(b)(iii) helium or hydrogen
The Sun is composed mainly of hydrogen (about 75%) and helium (about 25%), with small amounts of other elements.

(b)(iv) infrared; (visible) light; ultraviolet
The Sun emits energy across the electromagnetic spectrum, but most is in the infrared, visible, and ultraviolet regions.

Question

(a) Fig. 9.1 shows the speed–time graph for a short car journey.
(i) State a time when the car is accelerating.
(ii) Calculate the total distance travelled on this journey.
(b) The temperature of the air in the tyres increases during the journey.
State what happens to the motion of the air particles as the air warms up.
(c) The driver in the car brakes by using the brake pedal.
Fig. 9.2 shows the force exerted by the driver’s foot on the brake pedal.
Calculate the moment of the force from the driver’s foot about the pivot.
(d) As the car moves, electrostatic charges transfer to the car.
(i) State what causes the transfer of electrostatic charges.
(ii) State the name of the charged particles which move during this transfer of charge.
(iii) State the relative charge on the particles identified in (d)(ii).

Topic codes:

• Topic P1.2 — Motion (Part (a)(i) & (a)(ii))
• Topic P2.1.2 — Particle model (Part (b))
• Topic P1.5.2 — Turning effect of forces (Part (c))
• Topic P4.2.1 — Electrical charge (Part (d)(i), (d)(ii) & (d)(iii))

▶️ Answer/Explanation

(a)(i) Any time between t = 0 to t = 40 s
The car is accelerating when the speed is increasing. From the graph, the speed increases from 0 to 8 m/s during the first 40 seconds (the line slopes upwards). Any time within this interval shows acceleration.

(a)(ii) 560 m
Total distance travelled = area under the speed-time graph.
The graph forms a trapezium split into three sections:

  • Triangle 1 (0 to 40 s): \(\frac{1}{2} \times 40 \times 8 = 160\) m
  • Rectangle (40 to 80 s): \(40 \times 8 = 320\) m
  • Triangle 2 (80 to 100 s): \(\frac{1}{2} \times 20 \times 8 = 80\) m

Total distance = 160 + 320 + 80 = 560 m

(b) Particles move faster / have greater kinetic energy / \(E_k\)
As temperature increases, the air particles gain kinetic energy. They move more rapidly, colliding with each other and the tyre walls more frequently and with greater force. This increased motion causes the pressure in the tyre to rise.

(c) Moment = 720 Ncm
Moment = force × perpendicular distance from the pivot.
Moment = 40 N × 18 cm = 720 Ncm
(Note: The perpendicular distance is measured from the pivot to the line of action of the force. Here it is given as 18 cm.)

(d)(i) Friction
As the car moves, friction between the car and the air, and between the tyres and the road, causes the transfer of electrostatic charges. This is similar to charging by friction where electrons are transferred from one surface to another.

(d)(ii) Electrons
The charged particles that move during the transfer of electrostatic charge are electrons. They are negatively charged and are transferred from one material to another during friction.

(d)(iii) \(-1\)
Electrons have a relative charge of \(-1\). This means they have a negative charge equal in magnitude to the positive charge of a proton (\(+1\)).

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