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CIE iGCSE Co-Ordinated Science P1.4 Density Exam Style Questions Paper 4

Question

A student investigates a spring.
The student adds slotted masses to the spring to increase the force applied to the spring as shown in Fig. 3.1.
(a) The student records the length of the spring as it extends. Fig. 3.2 shows the results obtained by the student.
(i) Use Fig. 3.2 to determine the original length of the spring.
(ii) Use Fig. 3.2 to calculate the spring constant of the spring.
(iii) State the term used to describe point X on the graph.
(b) The slotted masses used by the student are made from steel.
Fig. 3.3 shows one of the slotted masses
Describe how the student determines the density of the steel used to make the slotted masses.
measurement 1 ___________
measurement 2 ___________
calculation ___________
(c) Fig. 3.4 shows how a long spring can be used to demonstrate wave motion.
(i) On Fig. 3.4 use a double headed arrow (\(\updownarrow\) or \(\leftrightarrow\)) to label the amplitude of the wave.
(ii) The wave shown in Fig. 3.4 is a transverse wave. Complete the sentence to describe the properties of a transverse wave.
Transverse waves are made by oscillations which act ___________ to the direction of energy transfer.

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654, 2025–2027 syllabus):

• Topic P1.5.1 — Effects of forces (Part (a))
• Topic P1.4 — Density (Part (b))
• Topic P3.1 — General properties of waves (Part (c))

▶️ Answer/Explanation

(a)(i)

The original (unloaded) length of the spring is read from where the graph line meets the y-axis (zero force).
Original length = 2.0 cm.
This is the length of the spring before any force is applied.

(a)(ii)

From the linear portion of the graph, using \( F = k \times x \) where \(x\) = extension (not total length).
Taking two points on the straight line, e.g. at \(F = 0\text{ N}\), length = 2.0 cm and at \(F = 5.0\text{ N}\), length = 12.0 cm, so extension = 10.0 cm.
Spring constant \( k = \frac{F}{x} = \frac{5.0}{10.0} = \mathbf{0.5} \) N/cm.

(a)(iii)

Point X is called the limit of proportionality.
Beyond this point, the extension is no longer proportional to the applied force (Hooke’s Law no longer applies).
The spring may become permanently deformed if stretched beyond the elastic limit.

(b)

Measurement 1: Measure the volume of the slotted mass using a displacement method (e.g. submerge it in a measuring cylinder or eureka can and record the volume of water displaced).
Measurement 2: Measure the mass of the slotted mass using a balance/scales.
Calculation: Calculate density using \( \rho = \frac{m}{V} \) (density = mass ÷ volume).

(c)(i)

The amplitude should be marked with a double-headed vertical arrow (\(\updownarrow\)) from the equilibrium (rest) position to the peak (crest) or trough of the wave.
Amplitude is the maximum displacement of a point on the wave from its equilibrium position.
It must be drawn from the centre dashed line to either the top or bottom of the wave.

(c)(ii)

Transverse waves are made by oscillations which act perpendicular / at right angles / 90° to the direction of energy transfer.
In the spring demonstration, the coils move up and down while the wave energy travels horizontally along the spring.
Examples of transverse waves include light waves and water waves.

Question

Polonium is a highly radioactive metal with no stable isotopes.
(a) Polonium-210 (\(^{210}_{84}Po\)) decays to form lead-206 (\(^{206}_{82}Pb\)).
The decay of polonium-210 is a one-step process.
(i) State the type of ionising radiation emitted when polonium-210 decays to lead-206.
(ii) The half-life of polonium-210 is 140 days.
The activity of a sample of polonium-210 is measured as 680 counts per minute.
Calculate the time taken, in days, for the activity to decrease to 85 counts per minute.
(b) Polonium is a solid at room temperature. The melting point of polonium is \(254\,^{\circ}C\).
(i) Explain, in terms of the motion and arrangement of atoms, why a fixed mass of solid polonium will occupy a smaller volume than the same mass of liquid polonium.
(ii) The density of solid polonium is \(9.4\,\text{g/cm}^3\).
Calculate the volume occupied by \(235\,\text{g}\) of solid polonium.

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654, 2025–2027 syllabus):

• Topic P5.2.1 — Detection of radioactivity (Part (a))
• Topic P2.1.2 — Particle model (Part (b)(i))
• Topic P1.4 — Density (Part (b)(ii))

▶️ Answer/Explanation

(a)(i) Alpha particle

The mass number decreases by 4 (\(210 \rightarrow 206\)) and the atomic/proton number decreases by 2 (\(84 \rightarrow 82\)).
This change is characteristic of the emission of an alpha particle (\(^4_2He\)).

(a)(ii) 420 days

The activity falls from 680 to 85 counts per minute: \(\dfrac{680}{85} = 8 = 2^3\), so 3 half-lives have passed.
Time taken \(= 3 \times 140 = 420\) days.

(b)(i) Atoms vibrate in a fixed, regular arrangement

Both samples contain the same number of atoms, since they have the same mass.
In the solid, atoms vibrate about fixed positions in a regular, closely-packed arrangement.
In the liquid, atoms are free to move and are arranged randomly/irregularly, with more space between them, so the liquid takes up a larger volume for the same mass.

(b)(ii) \(25\,\text{cm}^3\)

Volume is calculated using \(V = \dfrac{m}{\rho}\).
\(V = \dfrac{235}{9.4} = 25\,\text{cm}^3\).

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