CIE iGCSE Co-Ordinated Science P1.4 Density Exam Style Questions Paper 4
Question




Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654, 2025–2027 syllabus):
• Topic P1.5.1 — Effects of forces (Part (a))
• Topic P1.4 — Density (Part (b))
• Topic P3.1 — General properties of waves (Part (c))
▶️ Answer/Explanation
(a)(i)
The original (unloaded) length of the spring is read from where the graph line meets the y-axis (zero force).
Original length = 2.0 cm.
This is the length of the spring before any force is applied.
(a)(ii)
From the linear portion of the graph, using \( F = k \times x \) where \(x\) = extension (not total length).
Taking two points on the straight line, e.g. at \(F = 0\text{ N}\), length = 2.0 cm and at \(F = 5.0\text{ N}\), length = 12.0 cm, so extension = 10.0 cm.
Spring constant \( k = \frac{F}{x} = \frac{5.0}{10.0} = \mathbf{0.5} \) N/cm.
(a)(iii)
Point X is called the limit of proportionality.
Beyond this point, the extension is no longer proportional to the applied force (Hooke’s Law no longer applies).
The spring may become permanently deformed if stretched beyond the elastic limit.
(b)
Measurement 1: Measure the volume of the slotted mass using a displacement method (e.g. submerge it in a measuring cylinder or eureka can and record the volume of water displaced).
Measurement 2: Measure the mass of the slotted mass using a balance/scales.
Calculation: Calculate density using \( \rho = \frac{m}{V} \) (density = mass ÷ volume).
(c)(i)
The amplitude should be marked with a double-headed vertical arrow (\(\updownarrow\)) from the equilibrium (rest) position to the peak (crest) or trough of the wave.
Amplitude is the maximum displacement of a point on the wave from its equilibrium position.
It must be drawn from the centre dashed line to either the top or bottom of the wave.
(c)(ii)
Transverse waves are made by oscillations which act perpendicular / at right angles / 90° to the direction of energy transfer.
In the spring demonstration, the coils move up and down while the wave energy travels horizontally along the spring.
Examples of transverse waves include light waves and water waves.
Question
The activity of a sample of polonium-210 is measured as 680 counts per minute.
Calculate the time taken, in days, for the activity to decrease to 85 counts per minute.
Calculate the volume occupied by \(235\,\text{g}\) of solid polonium.
Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654, 2025–2027 syllabus):
• Topic P5.2.1 — Detection of radioactivity (Part (a))
• Topic P2.1.2 — Particle model (Part (b)(i))
• Topic P1.4 — Density (Part (b)(ii))
▶️ Answer/Explanation
(a)(i) Alpha particle
The mass number decreases by 4 (\(210 \rightarrow 206\)) and the atomic/proton number decreases by 2 (\(84 \rightarrow 82\)).
This change is characteristic of the emission of an alpha particle (\(^4_2He\)).
(a)(ii) 420 days
The activity falls from 680 to 85 counts per minute: \(\dfrac{680}{85} = 8 = 2^3\), so 3 half-lives have passed.
Time taken \(= 3 \times 140 = 420\) days.
(b)(i) Atoms vibrate in a fixed, regular arrangement
Both samples contain the same number of atoms, since they have the same mass.
In the solid, atoms vibrate about fixed positions in a regular, closely-packed arrangement.
In the liquid, atoms are free to move and are arranged randomly/irregularly, with more space between them, so the liquid takes up a larger volume for the same mass.
(b)(ii) \(25\,\text{cm}^3\)
Volume is calculated using \(V = \dfrac{m}{\rho}\).
\(V = \dfrac{235}{9.4} = 25\,\text{cm}^3\).
