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CIE iGCSE Co-Ordinated Science P1.5.2 Turning effect of forces Exam Style Questions Paper 1

Question

A metal bar has weight 50 N and length 2.0 m. The centre of gravity of the bar is 0.80 m from the left-hand end.

The bar is placed on a pivot at a point 0.40 m from the left-hand end.

What is the moment of the weight of the bar about the pivot?

A. 20 Nm
B. 40 Nm
C. 60 Nm
D. 80 Nm

▶️ Answer/Explanation
The moment = force × perpendicular distance from the pivot. The weight acts at the centre of gravity, 0.80 m from the left end.
The pivot is at 0.40 m from the left end. Distance from pivot = \(0.80 – 0.40 = 0.40\) m. Moment = \(50 \times 0.40 = 20\) Nm.
Answer: (A)

Question

The diagram shows a child of weight 240 N sitting on a see-saw (teeter-totter) at a distance of 1.6 m from the pivot.

What is the moment of the weight of the child about the pivot, with the correct unit?

A. 150 N m
B. 150 N/m
C. 384 N m
D. 384 N/m

▶️ Answer/Explanation
The moment of a force is calculated using \( \text{moment} = \text{force} \times \text{perpendicular distance from the pivot} \).
Substituting the values given: \( \text{moment} = 240 \times 1.6 = 384 \) N m.
The correct unit for a moment is newton-metres (N m), not N/m, so the answer is 384 N m.
Answer: (C)

Question

The diagram shows a triangular sheet of metal with sides of length 50 cm, 40 cm and 30 cm. The sheet is free to move about a pivot at the top corner, as shown.

A cord is attached to the bottom left corner of the sheet and pulled with a horizontal force of 5.0 N to the left.

What is the moment of the 5.0 N force about the pivot?

A. 150 N cm
B. 200 N cm
C. 250 N cm
D. 600 N cm

▶️ Answer/Explanation
The moment of a force is calculated using \( \text{moment} = \text{force} \times \text{perpendicular distance from the pivot} \).
The perpendicular distance from the pivot to the line of action of the horizontal force is the vertical side of the triangle, 40 cm.
So moment \( = 5.0 \times 40 = 200 \) N cm.
Answer: (B)

Question

A boy pulls a nail from a block of wood using a hammer, as shown.

The boy pulls the hammer with a force of 15 N in the position shown.

What is the moment produced about the pivot by the boy pulling on the hammer?

A. 0.90 N m  
B. 2.4 N m  
C. 3.3 N m  
D. 4.2 N m

▶️ Answer/Explanation
The moment of a force about a pivot is calculated using \(\text{moment} = \text{force} \times \text{perpendicular distance from the pivot}\).
\(\text{Moment} = 15\ \text{N} \times 0.22\ \text{m} = 3.3\ \text{N m}\).
Answer: (C)

Question

What is a suitable unit for the moment of a force?

A. N kg
B. N / kg
C. N m
D. N / m

▶️ Answer/Explanation
The moment of a force is calculated using \( \text{moment} = \text{force} \times \text{perpendicular distance from the pivot} \).
Force is measured in newtons (N) and distance is measured in metres (m), so the unit of moment is the product of these, N m.
N/kg is the unit for gravitational field strength, and N kg and N/m do not correspond to any standard physical quantity here.
Answer: (C)
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