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CIE iGCSE Co-Ordinated Science P1.6.1 Energy Exam Style Questions Paper 2

Question

A hydroelectric energy storage scheme stores energy by pumping water up a mountain into a lake behind a dam.

In 1.0 s, 10 000 kg of water is pumped into the lake and gains a height of 150 m. The efficiency of this process is 60%.

Gravitational field strength = 10 N/kg.

What is the energy input in 1.0 s?

A. 9.0 × 105 J
B. 2.5 × 106 J
C. 9.0 × 106 J
D. 2.5 × 107 J

▶️ Answer/Explanation
Useful energy output = gravitational PE gained: \(E_p = mgh = 10000 \times 10 \times 150 = 1.5\times10^7\text{ J}\).
Efficiency \(=\frac{\text{useful output}}{\text{total input}}\times 100\%\), so input \(=\frac{\text{output}}{\text{efficiency}}\).
Energy input \(= \frac{1.5\times10^7}{0.60} = 2.5\times10^7\text{ J}\).
Answer: (D)

Question

A machine has useful output energy of \(1000\text{ J}\) and wasted energy of \(300\text{ J}\).

Which expression is used to calculate the efficiency of the machine?

A. \(\frac{300}{1000+300} \times 100\%\)
B. \(\frac{300}{1000} \times 100\%\)
C. \(\frac{1000-300}{1000} \times 100\%\)
D. \(\frac{1000}{1000+300} \times 100\%\)

▶️ Answer/Explanation
Total input energy is \(\text{useful output} + \text{wasted energy} = 1000+300\).
\(\text{Efficiency} = \frac{1000}{1000+300} \times 100\%\).
Answer: (D)

Question

Which electrical device transfers chemical energy into electrical energy?

A. battery
B. lamp
C. electric motor
D. television

▶️ Answer/Explanation
A battery stores energy in the form of chemical potential energy within its internal chemicals.
When connected in a circuit, a chemical reaction inside the battery releases this energy and drives electrons around the circuit, transferring chemical energy into electrical energy.
A lamp, electric motor, and television all take electrical energy in and convert it to other forms (light/heat, kinetic, and light/sound respectively), rather than producing electrical energy.
Answer: (A)

Question

Which equation for kinetic energy (K.E.) is correct?

A. \(\text{K.E.} = \frac{1}{2}(mv)^2\)
B. \(\text{K.E.} = \frac{1}{2}mv^2\)
C. \(\text{K.E.} = mv^2\)
D. \(\text{K.E.} = mgh\)

▶️ Answer/Explanation
The standard formula for kinetic energy is \(\text{K.E.} = \frac{1}{2}mv^2\).
\(mgh\) is the formula for gravitational potential energy, not kinetic energy.
The other options incorrectly square the whole \(mv\) term or omit the \(\frac{1}{2}\).
Answer: (B)

Question

An object moving at speed \(v\) has kinetic energy \(E\).

What is the speed of the object when its kinetic energy is \(4.0E\)?

A. \(0.25v\)
B. \(2.0v\)
C. \(4.0v\)
D. \(16v\)

▶️ Answer/Explanation
Kinetic energy is given by \(E = \frac{1}{2}mv^2\), so energy is proportional to the square of the speed.
If the new kinetic energy is \(4.0E\), then \(v’^2\) must be 4 times \(v^2\), since mass stays constant.
Taking the square root, the new speed \(v’\) is \(2.0\) times the original speed \(v\).
Answer: (B)
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