CIE iGCSE Co-Ordinated Science P3.1 General properties of waves Exam Style Questions Paper 2
▶️ Answer/Explanation
Sound waves are longitudinal waves because the particles vibrate parallel to the direction of energy transfer. Radio waves are transverse waves because the oscillations are perpendicular to the direction of propagation. Option B correctly pairs sound wave (longitudinal) with radio wave (transverse).
✅ Answer: (B)
✅ Answer: (B)
▶️ Answer/Explanation
Rearranging \(v = f\lambda\) gives \(\lambda = \frac{v}{f}\).
Converting frequency: \(f = 3.0 \times 10^6\text{ Hz}\), so \(\lambda = \frac{1500}{3.0 \times 10^6} = 5.0 \times 10^{-4}\text{ m}\).
✅ Answer: (A)
Converting frequency: \(f = 3.0 \times 10^6\text{ Hz}\), so \(\lambda = \frac{1500}{3.0 \times 10^6} = 5.0 \times 10^{-4}\text{ m}\).
✅ Answer: (A)
▶️ Answer/Explanation
Frequency is defined as the number of complete waves (crests) passing a point per second.
Counting the number of crests passing in 30 seconds and dividing by 30 gives exactly this value.
Amplitude, wavelength and speed all require additional measurements (such as distance) that were not given here.
✅ Answer: (B)
Counting the number of crests passing in 30 seconds and dividing by 30 gives exactly this value.
Amplitude, wavelength and speed all require additional measurements (such as distance) that were not given here.
✅ Answer: (B)
▶️ Answer/Explanation
The wave speed equation is \( v = f\lambda \), which rearranges to \( \lambda = \frac{v}{f} \).
Substituting the values gives \( \lambda = \frac{330}{3300} \).
This works out to \( \lambda = 0.10 \) m.
✅ Answer: (A)
Substituting the values gives \( \lambda = \frac{330}{3300} \).
This works out to \( \lambda = 0.10 \) m.
✅ Answer: (A)
▶️ Answer/Explanation
Frequency is the number of complete waves passing a point per second. \(f = 5/20 = 0.25\text{ Hz}\).
✅ Answer: (A)
✅ Answer: (A)