CIE iGCSE Co-Ordinated Science P3.2.3 Thin converging lens Exam Style Questions Paper 3
Question



Topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):
• Topic P6.1 — The Solar System
• Topic P6.2.1 — The Sun as a star
• Topic P6.2.2 — Life cycle of stars
• Topic P3.2.3 — Thin converging lens
▶️ Answer/Explanation
(a)(i) Planet X is Jupiter.
From Table 10.1, planet X has a mass of \(2 \times 10^{27}\,\text{kg}\), which closely matches Jupiter’s known mass of approximately \(1.9 \times 10^{27}\,\text{kg}\). Jupiter is the most massive planet in the Solar System, making it the only candidate consistent with the table data.
(a)(ii) The Sun is 1000 times the mass of planet X — the student is incorrect.
\(\dfrac{2 \times 10^{30}}{2 \times 10^{27}} = 10^3 = 1000\). Since the ratio is 1000 and not 100, the student has made an error, likely a mistake with powers of 10. The Sun is therefore ten times more massive relative to planet X than the student claimed.
(b)(i) The two materials are gas and dust.
Protostars form when vast interstellar clouds of gas (mainly hydrogen and helium) and dust are drawn together by gravity. As the cloud collapses, temperature and pressure at the centre rise steadily until nuclear fusion ignites, marking the birth of a stable star.
(b)(ii) Stable star → red giant → planetary nebula + white dwarf.
When the hydrogen fuel in the Sun’s core is exhausted, it will expand and cool into a red giant. The outer layers will then be expelled as a planetary nebula, leaving behind the hot, dense core as a white dwarf that gradually cools over billions of years.
(c) Calculation:
\(\text{time} = \dfrac{\text{distance}}{\text{speed}} = \dfrac{1.5 \times 10^{11}}{3.0 \times 10^{8}} = 500\,\text{s}\)
\(500\,\text{s} \div 60 = 8.3\,\text{minutes} \approx 8\,\text{minutes}\)
Therefore, the time is approximately 8 minutes.
(d) Parallel rays from the Sun enter the converging lens and refract to meet at the principal focus on the dry grass.
Since the Sun is effectively at infinity, light rays arriving at the lens are parallel to the principal axis. The converging lens bends these rays inward so they all meet at a single focal point, concentrating light energy enough to raise the temperature of the grass and ignite it.
Question

State the speed of infrared waves in a vacuum.
State what is meant by an echo.

- draw a line to complete the path of ray 2
- draw the image formed
- label the image.

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):
• Topic P3.3 — Electromagnetic spectrum (Part (a))
• Topic P3.4 — Sound (Part (b))
• Topic P3.2.3 — Thin converging lens (Part (c))
• Topic P1.2 — Motion (Part (d))
▶️ Answer/Explanation
(a)(i) 
Frequency increases left to right, so infrared sits just before visible light.
Ultraviolet sits just after visible light, before γ-rays.
(a)(ii) 300 000 000 m/s
All electromagnetic waves, including infrared, travel at the same speed in a vacuum: \( 3.0 \times 10^8 \, \text{m/s} \).
(b) An echo is the reflection of a sound wave
Sound waves bounce off a hard surface and return to the source.
This reflected sound is heard as a delayed repeat of the original sound.
(c)(i) principal focus / focal point
F marks the point where parallel rays converge after passing through a converging lens.
(c)(ii) Ray 2 travels straight through the centre of the lens; image formed is inverted and real, located where rays 1 and 2 cross
Ray 2 (through the optical centre) continues in a straight line without bending.
The image forms where the two rays intersect, and is real, inverted, and diminished.
Label this intersection point as the “image”.
(d) 30 m/s
From the graph, total distance travelled in 6.0 s = 180 m.
Average speed \( = \dfrac{\text{distance}}{\text{time}} = \dfrac{180}{6.0} = 30 \, \text{m/s} \).
