CIE iGCSE Co-Ordinated Science P1.6.2 Work Exam Style Questions Paper 1
▶️ Answer/Explanation
Work done is calculated using \(W = F \times d\), where \(F\) is the force applied and \(d\) is the distance moved in the direction of the force.
Only quantities that appear in this equation — the size of the force and the distance moved — change the value of the work done.
Quantities such as time taken or the box’s mass do not appear in the work equation, so they do not directly affect work done.
✅ Answer: (A)
Only quantities that appear in this equation — the size of the force and the distance moved — change the value of the work done.
Quantities such as time taken or the box’s mass do not appear in the work equation, so they do not directly affect work done.
✅ Answer: (A)
▶️ Answer/Explanation
Work done is defined by the equation \(W = F \times d\), where \(F\) is force and \(d\) is the distance moved in the direction of the force.
Only the magnitude of the force and the distance moved determine the work done.
The mass, volume, or weight of the block do not appear in this equation and so do not directly affect work done.
✅ Answer: (A)
Only the magnitude of the force and the distance moved determine the work done.
The mass, volume, or weight of the block do not appear in this equation and so do not directly affect work done.
✅ Answer: (A)
▶️ Answer/Explanation
Work done is calculated using \( W = F \times d \), where F is force and d is the distance moved in the direction of the force.
Volume and time are not part of this equation, so any option including them can be ruled out.
The distance moved vertically corresponds to the height of the table, so the force used to lift the box and the height of the table are the two quantities needed.
✅ Answer: (A)
Volume and time are not part of this equation, so any option including them can be ruled out.
The distance moved vertically corresponds to the height of the table, so the force used to lift the box and the height of the table are the two quantities needed.
✅ Answer: (A)
▶️ Answer/Explanation
Work done is calculated as \( \text{work} = \text{force} \times \text{distance moved} \), where the force needed equals the weight of the load.
Lifting the load higher increases distance (more work), and the speed of lifting or the power of the crane affects only how quickly work is done, not the total amount of work.
Reducing the mass of the load reduces its weight, and therefore reduces the force needed, decreasing the total work done.
✅ Answer: (C)
Lifting the load higher increases distance (more work), and the speed of lifting or the power of the crane affects only how quickly work is done, not the total amount of work.
Reducing the mass of the load reduces its weight, and therefore reduces the force needed, decreasing the total work done.
✅ Answer: (C)
Question
A student walks up some steps at constant speed.
Which two quantities provide enough information so that the useful power produced by the student can be calculated?
A the weight of the student and the time taken
B the weight of the student and the total height of the steps
C the work done by the student and the time taken
D the work done by the student and the total height of the steps
▶️Answer/Explanation
Ans : C