CIE iGCSE Co-Ordinated Science P4.2.2 Electric current Exam Style Questions Paper 2
▶️ Answer/Explanation
Current is charge per unit time: \(I = \frac{Q}{t}\).
Convert time to seconds: \(3.0\) minutes \(= 180\,\text{s}\).
\(I = \frac{480}{180} = 2.7\,\text{A}\).
✅ Answer: (A)
Convert time to seconds: \(3.0\) minutes \(= 180\,\text{s}\).
\(I = \frac{480}{180} = 2.7\,\text{A}\).
✅ Answer: (A)
▶️ Answer/Explanation
First find the current using \( I = \frac{V}{R} = \frac{6.0}{30} = 0.2 \) A.
Charge is found using \( Q = It \), where \(t\) is the time in seconds.
Substituting gives \( Q = 0.2 \times 5.0 = 1.0 \) C.
✅ Answer: (A)
Charge is found using \( Q = It \), where \(t\) is the time in seconds.
Substituting gives \( Q = 0.2 \times 5.0 = 1.0 \) C.
✅ Answer: (A)
▶️ Answer/Explanation
In a series circuit, the same current (1.8 mA = 0.0018 A) flows through the variable resistor as through the ammeter.
Charge is calculated using (Q = It = 0.0018 \times 30 = 0.054) C.
✅ Answer: (A)
Charge is calculated using (Q = It = 0.0018 \times 30 = 0.054) C.
✅ Answer: (A)
Question
There is an alternating current (a.c.) in a metal wire.
Which statement about the current is correct?
(A) It is a flow of both positively and negatively charged particles.
(B) It is a flow of charged particles, first in one direction then in the opposite direction repeatedly.
(C) It is a flow of charged particles in both directions at the same time.
(D) It is a flow of charged particles steadily in one direction
▶️Answer/Explanation
Ans : B
Question
A charge of 480 C passes through a wire in 3.0 minutes.
What is the average current in the wire?
(A) 2.7A
(B) 24A
(C) 160A
(D) 1440A
▶️Answer/Explanation
Ans: A