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CIE iGCSE Co-Ordinated Science P4.5.5 The d.c. motor Exam Style Questions Paper 4

Question

(a) A student investigates a simple d.c. motor.
Fig. 10.1 shows a diagram of a simple d.c. motor.
(i) The motor consists of a current-carrying coil in a magnetic field. The coil experiences a turning effect.
State three ways the turning effect can be increased.
(ii) State the name of component X.
(iii) Describe how component X is used to give continuous rotation of the coil.
(b) Transformers are used in the distribution of electricity.
(i) State the type of transformer used at power stations to supply power to the electricity network.
(ii) Explain why the use of this transformer means power losses in transmission cables are smaller.
(c) A transformer is connected to a 230 V mains supply.
An output of 3.6 V is required.
The secondary coil has 720 turns.
Calculate the number of turns on the primary coil.

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

• Topic P4.5.5 — The d.c. motor
• Topic P4.5.6 — The transformer

▶️ Answer/Explanation

(a)(i) more turns of wire / more turns on the coil ; increase current ; stronger magnetic field
The turning effect (torque) on a coil in a magnetic field increases with the number of turns, the current flowing through the coil, and the strength of the magnetic field.

(a)(ii) split-ring commutator
The split-ring commutator is a device that reverses the direction of current through the coil every half-turn.

(a)(iii) reverses the direction of the current (in the coil) ; every half a turn
The commutator ensures that the current in the coil always flows in a direction that produces a turning force in the same rotational direction, allowing continuous rotation.

(b)(i) step-up
A step-up transformer increases the voltage for efficient long-distance transmission of electrical power.

(b)(ii) higher voltage ; means lower current (for same power transferred) ; (reference to) P = I²R or power loss proportional to current squared
By stepping up the voltage, the current in the transmission cables is reduced. Since power loss in cables is proportional to I²R, lower current significantly reduces energy losses.

(c) 46,000 turns

Using the transformer equation: Vₚ/Vₛ = Nₚ/Nₛ
230/3.6 = Nₚ/720
Nₚ = (230 × 720) ÷ 3.6 = 46,000

A step-down transformer reduces the high transmission voltage to a safer, usable voltage for domestic appliances.

Question

(a) Fig. 10.1 shows a simple d.c. motor.
(i) Explain why the side AB of the coil experiences a force when a current is in the coil.
(ii) Describe how forces on sides AB and CD cause a turning effect on the coil when a current is in the coil.
(iii) Describe how the split-ring commutator and brushes ensure the coil rotates continuously in the same direction.
 
(b) (i) Circle the component which is part of a basic transformer.
cell      permanent magnet      soft-iron core      straight wire
(ii) An ideal transformer has 2500 turns on the primary coil and 400 turns on the secondary coil.
There is a voltage of 230 V across the primary coil.
Calculate the voltage across the secondary coil.
(iii) The current in the secondary coil is 1.6 A.
Calculate the current in the primary coil.
(iv) State the assumption made in the calculation in (b)(iii).

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

• Topic P4.5.5 — The d.c. motor (Parts a(i), a(ii) & a(iii))
• Topic P4.5.6 — The transformer (Parts b(i), b(ii), b(iii) & b(iv))

▶️ Answer/Explanation

(a)(i) Why side AB experiences a force:
Side AB is a current-carrying conductor placed in a magnetic field (between the two magnets). The current flowing through the wire interacts with the magnetic field of the permanent magnets, producing a force on the wire (motor effect).

(a)(ii) How forces on AB and CD cause a turning effect:
The force on side AB is directed upwards while the force on side CD is directed downwards (or vice versa, depending on current direction). Since these forces act in opposite directions on opposite sides of the coil, they create a turning effect (moment) about the axis of rotation. This turning effect causes the coil to rotate.

(a)(iii) Role of split-ring commutator and brushes:
The split-ring commutator reverses the direction of the current in the coil every half-turn (180° of rotation). This ensures that the forces on sides AB and CD always act in the same direction relative to the rotation, maintaining continuous rotation in one direction. The brushes provide electrical contact with the rotating commutator while allowing it to spin freely.

(b)(i) Component of a basic transformer:
Soft-iron core — a transformer consists of a primary coil, a secondary coil, and a soft-iron core that links the two coils magnetically.

(b)(ii) Calculation of secondary voltage:
Using the transformer equation:

\(\frac{V_p}{V_s} = \frac{N_p}{N_s}\)

\(\frac{230}{V_s} = \frac{2500}{400}\)

\(V_s = \frac{230 \times 400}{2500} = \frac{92000}{2500} = 36.8 \, \text{V}\)

Voltage across secondary coil = 37 V (to 2 significant figures)

(b)(iii) Calculation of primary current:
For an ideal transformer (100% efficiency):

\(I_p V_p = I_s V_s\)

\(I_p \times 230 = 1.6 \times 36.8\)

\(I_p \times 230 = 58.88\)

\(I_p = \frac{58.88}{230} = 0.256 \, \text{A}\)

Current in primary coil = 0.26 A (to 2 significant figures)

(b)(iv) Assumption made:
The calculation assumes that the transformer is 100% efficient — meaning no energy is lost as heat in the coils or core, and all electrical power input is transferred to the output. In reality, transformers are not perfectly efficient due to resistance in the coils and eddy currents in the core.

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