CIE iGCSE Co-Ordinated Science P5.2.5 Applications and safety precautions Exam Style Questions Paper 2
▶️ Answer/Explanation
During \(\beta\)-emission, a neutron in the nucleus converts into a proton and an electron: \(n \rightarrow p + e^-\).
The emitted electron is the \(\beta\)-particle, and the new proton remains in the nucleus.
This raises the proton number (atomic number) by exactly \(1\), while the mass number stays the same.
✅ Answer: (B)
The emitted electron is the \(\beta\)-particle, and the new proton remains in the nucleus.
This raises the proton number (atomic number) by exactly \(1\), while the mass number stays the same.
✅ Answer: (B)
▶️ Answer/Explanation
Number of neutrons is found using \( \text{neutrons} = A – Z \).
For carbon-13: \( 13 – 6 = 7 \) neutrons.
For nitrogen-14: \( 14 – 7 = 7 \) neutrons, so both atoms have the same number of neutrons.
✅ Answer: (C)
For carbon-13: \( 13 – 6 = 7 \) neutrons.
For nitrogen-14: \( 14 – 7 = 7 \) neutrons, so both atoms have the same number of neutrons.
✅ Answer: (C)