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CIE iGCSE Co-Ordinated Science P5.2.5 Applications and safety precautions Exam Style Questions Paper 4

Question

(a) The isotope carbon-14 (C-14) decays to form an isotope of nitrogen (N) by emitting a beta particle.
Complete the decay equation for this nuclear decay.
(b) Thin aluminium foil is manufactured by passing thick sheets of aluminium between rollers.
Radioactive sources are used to measure and control the thickness of the aluminium foil, as shown in Fig. 11.1.
Suggest which type of radiation would be suitable for use in measuring and controlling the thickness of the aluminium foil. Explain your answer.
(c) Carbon-14 has a half-life of 5700 years.
A 5.0 g sample of wood from a living tree has an activity of 28 counts per minute due to the decay of carbon-14.
A 5.0 g sample of dead wood from the hull of an ancient wooden boat has an activity of 7 counts per minute due to the decay of carbon-14.
Calculate the age of the wood from the hull of the boat.
(d) Nuclear reactions occur in stable stars.
(i) State the type of nuclear reactions that take place in a stable star.
(ii) State what is produced in these nuclear reactions.

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

• Topic P5.2.3 — Radioactive decay
• Topic P5.2.4 — Half-life
• Topic P5.2.5 — Applications and safety precautions
• Topic P6.2.2 — Life cycle of stars

▶️ Answer/Explanation

(a) ¹⁴C → ⁰₋₁β + ¹⁴₇N
Beta decay involves a neutron converting into a proton and emitting a beta particle (electron). The mass number remains unchanged, but the atomic number increases by one.

(b) beta ; (beta) penetrates through thin aluminium foil (to be detected) / (beta) absorbed by thick aluminium foil (so not detected)
Beta radiation has intermediate penetrating power. It is suitable for thickness monitoring because the amount of radiation reaching the detector changes with foil thickness. Alpha would be completely absorbed, while gamma would pass through unaffected.

(c) 11,400 years

Activity has fallen from 28 to 7 counts/min
28 → 14 → 7 (2 half-lives)
Age = 2 × 5700 = 11,400 years

Each half-life reduces the activity by half. After two half-lives, the activity is a quarter of the original.

(d)(i) fusion
Stars produce energy through nuclear fusion, where lighter nuclei combine to form heavier nuclei, releasing enormous amounts of energy.

(d)(ii) helium ; and any named product heavier than hydrogen but lighter than iron ; energy
In stable stars, hydrogen nuclei fuse to form helium. In larger stars, further fusion produces heavier elements up to iron. Energy is released during these fusion reactions.

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