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CIE iGCSE Co-ordinated Sciences-P1.5.3 Centre of gravity- Study Notes- New Syllabus

CIE iGCSE Co-ordinated Sciences-P1.5.3 Centre of gravity – Study Notes

CIE iGCSE Co-ordinated Sciences-P1.5.3 Centre of gravity – Study Notes -CIE iGCSE Co-ordinated Sciences – per latest Syllabus.

Key Concepts:

Core

Understand what is meant by centre of gravity and know its position for regularly shaped objects (limited to rectangular blocks, spheres and cylinders)

Describe an experiment to determine the position of the centre of gravity of an irregularly shaped plane lamina

CIE iGCSE Co-Ordinated Sciences-Concise Summary Notes- All Topics

Centre of Gravity

The centre of gravity (CG) of an object is the point at which its entire weight can be considered to act.

  • It is the average position of all the weight of the object.

For regularly shaped objects made of uniform material, the CG lies at the geometrical centre.

Examples of Centre of Gravity in Regular Shapes:

  • Rectangular block: The CG is at the intersection of the diagonals, i.e. at the centre of the block.
  • Sphere: The CG is at the centre of the sphere.
  • Cylinder: The CG is at the midpoint of the central axis (the line running through the middle along its length).

Example:

A uniform solid cube has sides of length \( 12~\text{cm} \). Find the position of its centre of gravity.

▶️ Answer/Explanation

For a regular cube, the centre of gravity lies at its geometrical centre.

So, the CG is at half the length of each side: \( \dfrac{12}{2} = 6~\text{cm} \) from every face.

Therefore, the centre of gravity is at the point (6 cm, 6 cm, 6 cm) inside the cube.

Example:

A solid wooden cylinder of height \( 20~\text{cm} \) and radius \( 5~\text{cm} \) is placed on a table. Where is its centre of gravity?

▶️ Answer/Explanation

Since the cylinder is uniform and regularly shaped, its centre of gravity is at the midpoint of its central axis.

Thus, the CG is \( \dfrac{20}{2} = 10~\text{cm} \) from the base, along the central axis of the cylinder.

Determining the Centre of Gravity of an Irregular Plane Lamina (Plumb-line Method)

  • Aim: To find the position of the centre of gravity (CG) of an irregular flat lamina.
  • Apparatus: the irregular lamina (cardboard/metal), retort stand with clamp, pin or drawing pins, plumb line (string + small weight), set square/ruler, pencil, tracing paper (or thin paper), marker, scissors, tape.
  • Principle: When a lamina is freely suspended from any point, its CG lies vertically below the suspension point. By suspending from two (or more) different points and drawing the verticals through the suspension points, the intersection of these verticals locates the CG.

Procedure (step-by-step):

  1. Cut out the lamina and, if available, place it on tracing paper and trace its outline so you have a copy to mark on.
  2. Choose a convenient point near the edge of the lamina and fix a pin (or drawing pin) through this point so the lamina can hang freely when suspended. Attach the pin to the clamp on the stand so the lamina hangs without touching other surfaces.
  3. Hang a plumb line from the same clamp so that the string can hang freely next to the lamina. Allow the plumb line to come to rest (no swinging).
  4. Carefully mark a line on the tracing paper along the string — this gives the vertical line (line of action) through the suspension point. Use a pencil and ruler to extend the line across the traced outline.
  5. Remove the pin and choose a different suspension point on the lamina (preferably not collinear with the first). Repeat steps 2–4 and draw a second vertical line on the tracing paper.
  6. The intersection point of the two (or better, three) vertical lines is the position of the centre of gravity of the lamina. Mark that point clearly as the CG.
  7. As a check, you may suspend from a third point; its vertical should pass through (or very near) the same intersection point if the experiment is accurate.

Why this works (brief explanation):

  • When suspended, the lamina rotates until its weight acts directly below the suspension point. The plumb line shows the direction of the weight (vertical). The CG must lie somewhere on that vertical line. Two different suspension points give two verticals; their intersection is the unique point that lies on both lines the CG.

Precautions / Tips:

  • Make sure the lamina hangs freely and does not touch the clamp, stand or nearby surfaces when suspended.
  • Let the plumb line stop swinging before drawing the line — wait for steady equilibrium.
  • Use sharp pins and a fine pencil to reduce uncertainty in the marked lines.
  • Choose suspension points well apart (not very close together) to improve accuracy of intersection location.
  • If lines do not meet at a single point (due to small errors), take the area common to the crossing lines as an uncertainty region and estimate the CG as the centre of that region.

Sources of error and how to reduce them:

  • Poorly fixed pin or bent pin — use a straight, firm pin and secure clamp to avoid wobble.
  • Parallax when marking the line — view the plumb line and tracing paper directly from above when marking.
  • Wind or drafts causing the plumb line to swing — perform experiment in a draught-free area.
  • Imprecise tracing or drawing — use fine pencils and a ruler; repeat suspensions from a third point as a check.

Optional alternative method (balancing method):

  • Place the lamina on a narrow pointed support (knife-edge) and move the support until the lamina balances. Mark that support position as a line of possible CG positions. Repeat with the lamina rotated and balance again. The intersection of the lines gives the CG. This method is less used than plumb-line for irregular laminas but can confirm results.

Example :

A student performs the plumb-line experiment with an irregular lamina. When suspended from point A, the plumb line passes through point P. When suspended from point B, the plumb line also passes through point P. The student claims that point P must be the centre of gravity of the lamina. Explain why the student’s claim is correct.

▶️ Answer/Explanation

When the lamina is suspended from a point, its centre of gravity lies vertically below the suspension point, along the plumb line. Therefore, the CG must be somewhere on the first vertical line (from point A).

Similarly, when suspended from point B, the CG must also lie on the second vertical line. Since both verticals pass through the same point P, that intersection point must be the unique position of the centre of gravity.

Hence, the student is correct: point P is the centre of gravity of the lamina.

Effect of the Position of the Centre of Gravity on Stability

The stability of an object depends on the height of its centre of gravity and the size of its base area.

  • Lower centre of gravity ⟶ greater stability, because the line of action of weight is less likely to fall outside the base when tilted.
  • Higher centre of gravity ⟶ less stability, because a small tilt may cause the line of action of weight to pass outside the base, leading to toppling.
  • If the centre of gravity lies directly above the base, the object remains balanced (in equilibrium).
  • If the line of action of weight falls outside the base, the object will topple.

The center of mass (CM) is where the weight vector $\vec{w}$ acts. If the CM lies within the support base, the truck tips back to its position; if it lies outside, the truck overturns \[see (b)]. In contrast, the car in (a) is stable because its low CM makes tipping difficult.

Everyday Examples:

  • A wide-bottomed flask is more stable than a narrow-bottomed one, because its base area is larger and CG is lower.
  • A loaded bus has a higher CG than an empty bus, making it less stable when turning around bends.
  • Tightrope walkers carry a long balancing pole to lower their overall CG and increase stability.

Types of Equilibrium

Type of EquilibriumDescriptionExample
StableWhen displaced, the object returns to its original position because the centre of gravity is raised and then lowered.A cone resting on its base.
NeutralWhen displaced, the object stays in its new position because the centre of gravity does not change.A ball lying on a flat horizontal surface.
UnstableWhen displaced, the object continues to topple because the centre of gravity is lowered and does not return.A cone balanced on its tip.

Example:

A bus is designed with a low centre of gravity. Explain why this design increases the stability of the bus when it takes sharp turns.

▶️ Answer/Explanation

– A lower centre of gravity means the vertical line from the centre of gravity is more likely to fall within the base of the bus.

– When taking sharp turns, the bus tilts but does not topple easily because the turning effect (moment) due to its weight is smaller.

– Therefore, a low centre of gravity increases the stability of the bus, making it safer on the road.

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