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CIE IGCSE Mathematics (0580) Averages and range Study Notes

CIE IGCSE Mathematics (0580) Averages and range Study Notes - New Syllabus

CIE IGCSE Mathematics (0580) Averages and range Study Notes

LEARNING OBJECTIVE

  • Averages and Measures of Spread

Key Concepts: 

  • Averages and Measures of Spread

CIE iGCSE Maths (0580)  Study Notes – All topics

Averages and Measures of Spread

Averages and Measures of Spread : Mean

The mean is the sum of all data values divided by the number of values. It is also known as the arithmetic average.

Formula:

\( \text{Mean} = \dfrac{\text{Sum of values}}{\text{Number of values}} \)

The mean is best used when the data does not have extreme values (outliers) which can distort the average.

Example:

Find the mean of the following data: 5, 9, 12, 15, 19.

▶️ Answer/Explanation

Sum = 5 + 9 + 12 + 15 + 19 = 60

Number of values = 5

Mean = \( \dfrac{60}{5} = \boxed{12} \)

Example:

The table shows the number of books read by a group of students last month.

Books ReadNumber of Students (Frequency)
04
16
25
33
▶️ Answer/Explanation

Use the formula for mean with frequencies:

\( \text{Mean} = \dfrac{\sum fx}{\sum f} \)

Where \( f \) is the frequency and \( x \) is the value

  • \( (0 \times 4) + (1 \times 6) + (2 \times 5) + (3 \times 3) = 0 + 6 + 10 + 9 = 25 \)
  • Total frequency = 4 + 6 + 5 + 3 = 18

Mean = \( \dfrac{25}{18} \approx \boxed{1.39} \)

Note: The mean is affected by extreme values. If there are unusually large or small numbers in the data, consider using the median instead.

Averages and Measures of Spread : Median

The median is the middle value when data is arranged in numerical order. It is not affected by extreme values (outliers) and is useful for skewed data.

How to find the median:

  • If the number of values is odd, the median is the middle number.
  • If the number of values is even, the median is the average of the two middle numbers.

Example:

Find the median of the following values: 9, 5, 13, 7, 11.

▶️ Answer/Explanation

Arrange in order: 5, 7, 9, 11, 13

Middle value = \( \boxed{9} \)

Example:

Find the median of 4, 8, 12, 16, 20, 24.

▶️ Answer/Explanation

Arrange in order (already done)

Middle values = 12 and 16

Median = \( \dfrac{12 + 16}{2} = \dfrac{28}{2} = \boxed{14} \)

Median from a frequency table:

  1. Find the cumulative frequency.
  2. Locate the middle value ( \( \dfrac{n+1}{2} \) if individual data or \( \dfrac{n}{2} \) if grouped).
  3. Identify the class that contains the median.

Example:

The table shows the ages of students in a club.

Age (years)Frequency
10–125
13–158
16–187
▶️ Answer/Explanation

Total frequency = 5 + 8 + 7 = 20

Median position = \( \dfrac{20}{2} = 10 \)

Cumulative frequency: 5 (first class),(5+8)= 13 (second class), (5+8+7)=20 (third class)

The 10th value is in the 13–15 class → this is the median class.

So, median age is in range \( \boxed{13\text{–}15} \)

Note: The median is not affected by extreme values. It gives a better picture of typical values in skewed distributions.

Averages and Measures of Spread : Mode

The mode is the value that appears most frequently in a data set. A data set can have:

  • One mode (unimodal)
  • Two modes (bimodal)
  • No mode (if all values occur equally)

Mode is especially useful for categorical or discrete data.

Example:

Find the mode of the following values: 3, 5, 5, 7, 9, 5, 11.

▶️ Answer/Explanation

5 appears 3 times, more than any other number.

Mode = \( \boxed{5} \)

Example :

The table shows the number of goals scored in matches.

GoalsFrequency
02
15
28
33
▶️ Answer/Explanation

Goal value 2 has the highest frequency (8 times).

Mode = \( \boxed{2} \)

Note: The mode may not exist or may not be useful for continuous data unless data is grouped into intervals. It is best for identifying the most common value.

Averages and Measures of Spread : Quartiles

Quartiles divide a data set into four equal parts. They are useful for describing the spread and identifying outliers.

  • Lower Quartile (Q1): The median of the lower half of the data (below the overall median).
  • Upper Quartile (Q3): The median of the upper half of the data (above the overall median).
  • Interquartile Range (IQR): The difference between Q3 and Q1: \( \text{IQR} = Q_3 – Q_1 \)

Quartiles are used to measure spread and detect skewness or outliers.

Example:

Find the lower and upper quartiles for the data: 2, 4, 6, 8, 10, 12, 14

▶️ Answer/Explanation

Step 1: Arrange the data (already in order).

Step 2: Median = middle value = 8

Step 3: Lower half = 2, 4, 6 → Q1 = median = 4

Step 4: Upper half = 10, 12, 14 → Q3 = median = 12

Answer: \( Q_1 = \boxed{4},\quad Q_3 = \boxed{12} \)

Example:

Find the quartiles for the data: 5, 6, 7, 8, 9, 10, 12, 14

▶️ Answer/Explanation

Step 1: Data is in order.

Step 2: Total values = 8 (even number), so median = average of 4th and 5th values = \( \frac{8 + 9}{2} = 8.5 \)

Step 3: Lower half = 5, 6, 7, 8 → Q1 = median = \( \frac{6 + 7}{2} = 6.5 \)

Step 4: Upper half = 9, 10, 12, 14 → Q3 = median = \( \frac{10 + 12}{2} = 11 \)

Answer: \( Q_1 = \boxed{6.5},\quad Q_3 = \boxed{11} \)

Tip: Use quartiles to find the IQR (spread of middle 50% of the data), especially useful when the data contains outliers.

Averages and Measures of Spread : Range and Interquartile Range

Measures of spread tell us how spread out the values in a data set are. Two common measures are:

  • Range: Difference between the largest and smallest value
  • Interquartile Range (IQR): Difference between the upper quartile (Q3) and the lower quartile (Q1):
    \( \text{IQR} = Q_3 – Q_1 \)

Use: IQR is a better measure of spread than range when data contains extreme values or outliers.

Example:

Find the range and interquartile range of the data: 2, 4, 6, 8, 10, 12, 14

▶️ Answer/Explanation

Range = largest − smallest = 14 − 2 = \( \boxed{12} \)

Q1 = 4, Q3 = 12

IQR = \( Q_3 – Q_1 = 12 – 4 = \boxed{8} \)

Example:

The data set is: 3, 7, 8, 10, 12, 13, 16, 18, 20

▶️ Answer/Explanation

Step 1: Range = 20 − 3 = \( \boxed{17} \)

Step 2: Median = 12

Lower half = 3, 7, 8, 10 → Q1 = average of 7 and 8 = \( \boxed{7.5} \)

Upper half = 13, 16, 18, 20 → Q3 = average of 16 and 18 = \( \boxed{17} \)

IQR = \( 17 – 7.5 = \boxed{9.5} \)

Tip: The IQR is not affected by outliers, so it is useful for comparing the spread of skewed data.

Estimate of the Mean for Grouped Data

Estimate of the Mean for Grouped Data

For grouped data (whether discrete or continuous), we cannot know the exact values, so we estimate the mean using the midpoints of the class intervals.

Steps:

  • Find the midpoint of each class
  • Multiply each midpoint by its frequency
  • Add all the results to get the total of \( fx \)
  • Divide by the total frequency to find the estimated mean

Formula: \( \text{Estimated Mean} = \dfrac{\sum fx}{\sum f} \)

Example:

The table shows the time (in minutes) taken by 30 students to complete a task: Estimated the mean .

Time (min)Frequency
0 – 106
10 – 2010
20 – 308
30 – 404
40 – 502
▶️ Answer/Explanation

Midpoints: 5, 15, 25, 35, 45

Calculate \( fx \):

  • $5 × 6 = 30$
  • $15 × 10 = 150$
  • $25 × 8 = 200$
  • $35 × 4 = 140$
  • $45 × 2 = 90$

\( \sum fx = 30 + 150 + 200 + 140 + 90 = 610 \)

\( \sum f = 6 + 10 + 8 + 4 + 2 = 30 \)

Estimated mean = \( \dfrac{610}{30} = \boxed{20.33 \text{ minutes}} \)

Example :

The table shows the number of goals scored by a team over several matches:Estimated the mean .

GoalsFrequency
03
16
25
34
42
▶️ Answer/Explanation

This is discrete data, so no midpoint needed.

  • $0 × 3 = 0$
  • $1 × 6 = 6$
  • $2 × 5 = 10$
  • $3 × 4 = 12$
  • $4 × 2 = 8$

\( \sum fx = 0 + 6 + 10 + 12 + 8 = 36 \)

\( \sum f = 3 + 6 + 5 + 4 + 2 = 20 \)

Estimated mean = \( \dfrac{36}{20} = \boxed{1.8 \text{ goals}} \)

Modal Class

Modal Class

For grouped data, we cannot determine an exact mode. Instead, we identify the modal class — the class interval with the highest frequency.

Key Point: The modal class represents the class where data values occur most frequently.

Example:

For the given table shows the number of hours students spent studying , Find the modal class

HoursFrequency
0–24
2–47
4–612
6–89
8–105
▶️ Answer/Explanation

Look for the class with the highest frequency:

Maximum frequency = 12 (in class 4–6)

Modal class = \( \boxed{4\text{–}6} \)

Example:

The grouped frequency distribution below shows the marks obtained by students: , Find the modal class

MarksFrequency
0–102
10–206
20–3011
30–4014
40–509
▶️ Answer/Explanation

Class with highest frequency = 14 (in 30–40)

Modal class = \( \boxed{30\text{–}40} \)

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