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CIE IGCSE Mathematics (0580) Circles, arcs and sectors Study Notes

CIE IGCSE Mathematics (0580) Circles, arcs and sectors Study Notes - New Syllabus

CIE IGCSE Mathematics (0580) Circles, arcs and sectors Study Notes

LEARNING OBJECTIVE

  • Circles

Key Concepts: 

  • Circles and its Arc Length and Sector Area

CIE iGCSE Maths (0580)  Study Notes – All topics

Circles

Circles

A circle is a round shape with all points on its boundary equidistant from the center.

Parts of a Circle:

  • Radius (r): Distance from the center to any point on the circle.
  • Diameter (d): Distance across the circle through the center. \( d = 2r \)
  • Circumference: The perimeter (distance around) of the circle.
  • Area: The space enclosed by the circle.

Key Formulas:

  • Circumference:
        \( C = \pi d \) or \( C = 2\pi r \)
  • Area:
        \( A = \pi r^2 \)
  • Use \( \pi \approx 3.14 \) or calculator’s π button for accuracy.

Important Notes:

  • Use radius if not told otherwise.
  • Always include correct units (e.g. cm² for area, cm for circumference).
  • Round your final answer appropriately (usually to 2 decimal places unless told otherwise).

Example:

Find the circumference of a circle with radius 7 cm.

▶️ Answer/Explanation

Using \( C = 2\pi r \):

\( C = 2 \times \pi \times 7 = 14\pi \approx 43.98 \ \text{cm} \)

Answer: 43.98 cm

Example:

Find the area of a circle with a diameter of 10 cm.

▶️ Answer/Explanation

Radius = \( \frac{10}{2} = 5 \ \text{cm} \)

Using \( A = \pi r^2 \):

\( A = \pi \times 5^2 = 25\pi \approx 78.54 \ \text{cm}^2 \)

Answer: 78.54 cm²

Example:

A circular garden has a path of width 1.5 m running all around it. The radius of the garden without the path is 7 m. Find:

  1. the area of the path
  2. the total length of fencing required to go around the outer edge of the path
▶️ Answer/Explanation

outer radius (including path):

\( R = 7 + 1.5 = 8.5 \ \text{m} \)

\( A_{\text{outer}} = \pi R^2 = \pi (8.5)^2 = \pi \times 72.25 \approx 227.00 \ \text{m}^2 \)

\( A_{\text{inner}} = \pi r^2 = \pi (7)^2 = \pi \times 49 \approx 153.94 \ \text{m}^2 \)

Area of the path = outer area − inner area:

\( A_{\text{path}} = 227.00 – 153.94 = 73.06 \ \text{m}^2 \)

Circumference of the outer edge for fencing:

\( C = 2\pi R = 2\pi \times 8.5 \approx 2 \times 3.1416 \times 8.5 \approx 53.41 \ \text{m} \)

Arc Length and Sector Area

Arc Length and Sector Area

Arc length is the distance along the curved line of a circle (or any curve)In the context of a circle, it’s a portion of the circle’s circumference between two points on the curve. 

 

  • Arc Length:
         \( \text{Arc Length} = \frac{\theta}{360} \times 2\pi r \)

A sector is a portion of a circle bounded by two radii and the arc between them. A full circle has an angle of 360°.

  • Sector Area:
         \( \text{Sector Area} = \frac{\theta}{360} \times \pi r^2 \)
  • \( \theta \) is the angle of the sector in degrees.

Important Notes:

  • If given the diameter, halve it to find radius.
  • Make sure the angle is in degrees, and use accurate π values if allowed.
  • The arc is part of the circle’s circumference, the sector is part of its area.

Example:

Find the length of an arc of a circle with radius 6 cm and angle 90°.

▶️ Answer/Explanation

Using \( \text{Arc Length} = \frac{\theta}{360} \times 2\pi r \):

\( \frac{90}{360} \times 2\pi \times 6 = \frac{1}{4} \times 12\pi = 3\pi \approx 9.42 \ \text{cm} \)

Answer: 9.42 cm

Example:

The angle of a sector is 135°, and the area of the sector is 81.4 cm². Find the arc length, giving your answer to 2 decimal places.

▶️ Answer/Explanation

We are given sector area and angle, and we must find arc length. First, find the radius using:

\( \text{Sector Area} = \frac{\theta}{360} \times \pi r^2 \)

\( 81.4 = \frac{135}{360} \times \pi r^2 \Rightarrow 81.4 = \frac{3}{8} \pi r^2 \)

\( r^2 = \frac{81.4 \times 8}{3\pi} = \frac{651.2}{3\pi} \approx \frac{651.2}{9.4248} \approx 69.09 \)

\( r \approx \sqrt{69.09} \approx 8.31 \ \text{cm} \)

Now use arc length formula: \( \text{Arc Length} = \frac{\theta}{360} \times 2\pi r \)

\( = \frac{135}{360} \times 2\pi \times 8.31 = \frac{3}{8} \times 2\pi \times 8.31 \)

\( = \frac{3}{4} \times \pi \times 8.31 \approx 0.75 \times 3.1416 \times 8.31 \approx 19.58 \ \text{cm} \)

Answer: 19.58 cm

Example:

In a circle with a radius of 14 cm, a sector has an arc length of 16 cm. Find the area of the sector.

▶️ Answer/Explanation

First, use arc length to find the angle:

\( \text{Arc Length} = \frac{\theta}{360} \times 2\pi r \)

\( 16 = \frac{\theta}{360} \times 2\pi \times 14 \Rightarrow 16 = \frac{\theta}{360} \times 28\pi \)

\( \frac{16}{28\pi} = \frac{\theta}{360} \Rightarrow \theta = \frac{16 \times 360}{28\pi} \approx \frac{5760}{87.9646} \approx 65.47^\circ \)

Now use sector area formula:

\( \text{Area} = \frac{\theta}{360} \times \pi r^2 = \frac{65.47}{360} \times \pi \times 14^2 \)

\( \approx 0.18186 \times \pi \times 196 \approx 0.18186 \times 615.752 \approx 112.01 \ \text{cm}^2 \)

Answer: 112.01 cm²

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