CIE IGCSE Mathematics (0580) Exponential growth and decay Study Notes - New Syllabus
CIE IGCSE Mathematics (0580) Exponential growth and decay Study Notes
LEARNING OBJECTIVE
- Exponential Growth and Decay
Key Concepts:
- Exponential Growth and Decay
Exponential Growth and Decay
Exponential Growth and Decay
Exponential growth and decay describe situations where the rate of change of a quantity is proportional to the current value. This means the amount increases or decreases by the same percentage in each time period.
- Growth: When a quantity increases over time (e.g. population, investments).
- Decay: When a quantity decreases over time (e.g. depreciation, radioactive decay).
General Formula
$\text{Final Amount} = \text{Initial Amount} \times (1 \pm r)^n $
- \( r \): rate of growth or decay as a decimal (e.g. $5\% → 0.05$)
- \( n \): number of time periods (years, months, etc.)
- Use \( +r \) for growth and \( -r \) for decay
Why Exponential?
The word “exponential” comes from the fact that the quantity is multiplied by a fixed number repeatedly — the variable is in the exponent. This leads to rapid changes compared to linear growth or decay.
Important Characteristics:
- Growth curves: become steeper over time.
- Decay curves: fall rapidly at first, then level off.
- Useful for modeling real-life processes like compound interest, inflation, population growth, depreciation, and cooling.
Graphical Interpretation:
- Exponential Growth: Curve slopes upwards — it gets steeper.
- Exponential Decay: Curve slopes downwards — it flattens out over time.
Example:
A town has a population of 12,000. It increases by 4% per year. What will the population be after 3 years?
▶️ Answer/Explanation
\( r = 0.04,\ n = 3 \)
\( \text{Population} = 12000 \times (1 + 0.04)^3 \)
\( = 12000 \times (1.04)^3 = 12000 \times 1.124864 \)
\( \approx 13,498.37 \)
Answer: Approximately 13,498 people
Example:
A car is bought for $25,000. It depreciates by 15% per year. What will be its value after 4 years?
▶️ Answer/Explanation
\( r = 0.15,\ n = 4 \)
\( \text{Value} = 25000 \times (1 – 0.15)^4 \)
\( = 25000 \times (0.85)^4 = 25000 \times 0.52200625 \)
\( \approx 13,050.16 \)
Answer: Approximately $\$13,050.16$