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CIE IGCSE Mathematics (0580) Parallel lines Study Notes

CIE IGCSE Mathematics (0580) Parallel lines Study Notes - New Syllabus

CIE IGCSE Mathematics (0580) Parallel lines Study Notes

LEARNING OBJECTIVE

  • Parallel Lines

Key Concepts: 

  • Parallel Lines

CIE iGCSE Maths (0580)  Study Notes – All topics

Parallel Lines

Two straight lines are parallel if they have the same gradient (slope). They never intersect and are always the same distance apart.

Key Fact:

If line A has the equation \( y = mx + c_1 \), then any line parallel to it has the equation \( y = mx + c_2 \), where \( m \) is the same, but \( c_2 \neq c_1 \).

Steps to Find the Equation of a Line Parallel to a Given Line:

  1. Identify the gradient \( m \) from the given line.
  2. Use the point given to substitute into \( y = mx + c \) and solve for \( c \).
  3. Write the final equation in the form \( y = mx + c \).

Example :

Find the equation of the line parallel to \( y = 4x – 1 \) that passes through the point (2, 5).

▶️ Answer/Explanation

Gradient \( m = 4 \) (same as the given line)

Use \( y = mx + c \) and point (2, 5): \( 5 = 4(2) + c \Rightarrow 5 = 8 + c \Rightarrow c = -3 \)

Answer: \( y = 4x – 3 \)

Example :

A line is parallel to \( y = -\frac{1}{2}x + 7 \) and passes through (0, –3). Find its equation.

▶️ Answer/Explanation

Gradient \( m = -\frac{1}{2} \)

Use point (0, –3): \( y = mx + c \Rightarrow -3 = -\frac{1}{2}(0) + c \Rightarrow c = -3 \)

Answer: \( y = -\frac{1}{2}x – 3 \)

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