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IGCSE Chemistry Mock – Set 3 Paper 2-Updated 2026

IGCSE Chemistry Mock – Set 3 Paper 2 – Updated 2026

Preparing for your CIE IGCSE Chemistry exam can be daunting, but with the right approach, you can achieve your goals with CIE iGCSE Chemistry Mock test.

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CIE iGCSE Chemistry Mock test – All Sets

Question

Some information about two dilute acids is shown.

dilute acidacid concentration in mol/dm3pH
nitric acid0.11.0
propanoic acid0.42.6

Three statements about the acids are listed.

  1. Nitric acid has a lower pH because it dissociates more than propanoic acid.
  2. Propanoic acid has a lower concentration of hydrogen ions than nitric acid.
  3. Propanoic acid has a higher pH because it has a higher concentration.

Which statements are correct?

A) 1 and 2
B) 1 and 3
C) 2 only
D) 3 only

▶️ Answer/Explanation
Solution

Ans: A

Let’s analyze each statement:

Statement 1: Correct. Nitric acid is a strong acid that completely dissociates, while propanoic acid is a weak acid that only partially dissociates. This explains why nitric acid has a lower pH despite its lower concentration.

Statement 2: Correct. Even though propanoic acid has a higher concentration (0.4 mol/dm3 vs 0.1 mol/dm3), its partial dissociation means it produces fewer H+ ions than the completely dissociated nitric acid.

Statement 3: Incorrect. The higher pH of propanoic acid is due to its weaker acidity (less dissociation), not its higher concentration. In fact, if it were a strong acid, higher concentration would lead to lower pH.

Question 

Lead(II) sulfate is an insoluble salt.

Which method is suitable for obtaining pure solid lead(II) sulfate?

A) Mix aqueous lead(II) nitrate and aqueous potassium sulfate, heat to evaporate all of the water, collect the solid and then wash and dry it.
B) Mix aqueous lead(II) nitrate and aqueous potassium sulfate, filter, collect the filtrate, crystallise, then wash and dry the crystals.
C) Mix aqueous lead(II) nitrate and dilute sulfuric acid, filter, then wash and dry the residue.
D) Titrate aqueous lead(II) hydroxide with dilute sulfuric acid, crystallise, then wash and dry the crystals.

▶️ Answer/Explanation
Solution

Ans: C

For preparing insoluble salts like lead(II) sulfate:

1. Option A: Incorrect because heating to evaporate water would leave behind all dissolved salts (including soluble byproducts), not just the insoluble PbSO4.

2. Option B: Incorrect because collecting the filtrate would give you the soluble products, not the insoluble PbSO4 which would be in the residue.

3. Option C: Correct. The steps are:

  • Mix solutions to form the insoluble salt: Pb(NO3)2 + H2SO4 → PbSO4↓ + 2HNO3
  • Filter to collect the insoluble PbSO4 as residue
  • Wash with distilled water to remove soluble impurities
  • Dry to obtain pure PbSO4

4. Option D: Incorrect because titration is used for soluble salts, and lead(II) hydroxide is itself insoluble.

Question 

Tennessine, Ts, is at the bottom of Group VII of the Periodic Table.

What are the predicted properties of tennessine at room temperature?

A) a black solid, more dense than iodine
B) a black solid, more reactive than iodine
C) a colourless gas, less dense than chlorine
D) a colourless gas, less reactive than chlorine

▶️ Answer/Explanation
Solution

Ans: A

Tennessine is in Group VII (halogens) and at the bottom of the group. We can predict its properties by looking at the trend in Group VII elements:

1. As we go down Group VII, the elements change from gases (F₂, Cl₂) to liquids (Br₂) to solids (I₂).

2. The density increases down the group (I₂ is a shiny black solid).

3. Reactivity decreases down the group (fluorine is most reactive, iodine less so).

Therefore, tennessine would be expected to be a black solid (like iodine but more dense) and less reactive than iodine. This matches option A.

IGCSE Chemistry Mock Paper 2 - Full Access
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