Home / iGCSE / CIE iGCSE Mathematics

IGCSE Mathematics Mock – Set 3 Paper 3-Updated 2026

IGCSE Mathematics Mock – Set 3 Paper 3- Updated 2026

Preparing for your CIE IGCSE Mathematics exam can be daunting, but with the right approach, you can achieve your goals with CIE iGCSE Mathematics Mock test.

Ace your CIE iGCSE Mathematics exam! Find exam-style questions, detailed notes, and helpful resources to boost your understanding.

iGCSE Practice Questions, Past Papers, Flashcards and notes available for iGCSE Students at IITian Academy.

CIE iGCSE Mathematics Mock test – All Sets

Question 

(a) Write the number six million and thirty in figures.

(b) Write 7.896 correct to 2 decimal places.

(c) 

From this list of numbers, write down:

(i) a multiple of 16
(ii) a factor of 24
(iii) a cube number
(iv) a prime number.

(d) Put one pair of brackets into this calculation to make it correct: \(10 – 12 \div 4 + 2 = 8\)

(e) By writing each number in the calculation correct to 1 significant figure, find an estimate for the value of

\(\frac{8.65 \times 596}{0.047}\)

You must show all your working.

(f) Calculate \(\frac{(8 \times 10^3) \times (10 \times 10^2)}{6}\).
Give your answer in standard form.

(g) \(216 = 2^{3} /times 3^{3}\)

Write 2160 as a product of its prime factors.

▶️ Answer/Explanation
Solution

(a) 6,000,030 – Just write six million as 6,000,000 and thirty as 30.

(b) 7.90 – Look at the third decimal (6) to round the second decimal (9) up.

(c) (i) 48 (16×3) (ii) 8 or 24 (both divide 24) (iii) 8 (2×2×2) (iv) 41 (only divisible by 1 and itself).

(d) \(10 – 12 \div (4 + 2) = 8\) – The brackets make the division happen first.

(e) ≈600 – Round numbers: 8.65≈9, 596≈600, 0.047≈0.05. Then 9×600÷0.05=600.

(f) \(1.33 \times 10^6\) – Calculate 8×10=80, 10³×10²=10⁵, so (80×10⁵)/6≈1.33×10⁶.

(g) \(2^4 \times 3^3 \times 5\) – Break down 2160: 2160=216×10=6³×2×5=2³×3³×2×5=2⁴×3³×5.

IGCSE Mathematics Mock Paper 3 - Full Access
Scroll to Top