iGCSE Physics (0625) 3.2.3 Thin lens-Exam Style Questions- New Syllabus
▶️ Answer/Explanation
Detailed solution:
The ray diagram shows light rays from the object actually meeting at a point on the opposite side of the lens, which defines the image as real.
The arrow representing the image points downwards while the object points upwards, confirming the image is inverted.
By comparing the heights, the vertical length of the image arrow is clearly shorter than that of the object arrow, meaning it is diminished.
This occurs when the object is placed at a distance u > 2f from the optical centre of a converging lens.
Therefore, the correct description is real, inverted, and diminished, which corresponds to option A.
▶️ Answer/Explanation
Detailed solution:
The ray diagram shows the object placed between $F$ and $2F$ from a converging lens. When an object is in this position, the rays converge on the opposite side beyond $2F$ to form a real image. Observing the diagram, the image arrow points downwards, indicating it is inverted. Comparing heights, the image is clearly larger than the object, meaning it is enlarged ($M > 1$). Therefore, the image is both enlarged and inverted, making option A correct.
▶️ Answer/Explanation
Detailed solution:
The ray diagram shows light rays originating from the object, passing through the lens, and actually intersecting at a point on the opposite side. Because the rays physically meet, the image is real and can be projected onto a screen. The resulting image arrow points downwards, opposite to the orientation of the object, confirming it is inverted. Visually, the image is also larger than the object, making it enlarged, though only “real and inverted” are required to identify the correct row. Therefore, the terms that accurately describe this image are real and inverted.