IB DP Chemistry Mock Exam HL Paper 1A Set 5 - 2025 Syllabus
IB DP Chemistry Mock Exam HL Paper 1A Set 5
Prepare for the IB DP Chemistry Exam with our comprehensive IB DP Chemistry Exam Mock Exam HL Paper 1A Set 5. Test your knowledge and understanding of key concepts with challenging questions covering all essential topics. Identify areas for improvement and boost your confidence for the real exam
Question
| Option | Electron-domain geometry | Molecular geometry |
|---|---|---|
| A | octahedral | tetrahedral |
| B | octahedral | square planar |
| C | tetrahedral | tetrahedral |
| D | tetrahedral | square planar |
▶️ Answer/Explanation
In \(\mathrm{XeCl_4}\), xenon has \(6\) electron domains: \(4\) bonding pairs and \(2\) lone pairs.
With six electron domains, the electron-domain geometry is octahedral.
The two lone pairs occupy opposite positions, leaving the four chlorine atoms arranged in a square planar shape.
✅ Answer: B
Question
(B) Group 17 elements have more filled energy levels.
(C) Group 17 elements have more paired electrons.
(D) Group 17 elements have more protons in the nucleus.
▶️ Answer/Explanation
Within the same period, Group 17 elements have a higher nuclear charge (more protons) than Group 1 elements.
This stronger attraction to the nucleus makes it harder to remove an electron, resulting in a higher ionization energy.
✅ Answer: (D)
Question
(B) [Ar]4s13d5
(C) [Ar]3d4
(D) [Ar]3d5
▶️ Answer/Explanation
Cr atomic number = 24, electron configuration: [Ar]4s13d5
Cr2+ loses 2 electrons. The 4s electron is removed first, then one 3d electron.
So: [Ar]4s13d5 → remove 4s1 → [Ar]3d5 → remove one 3d → [Ar]3d4
✅ Answer: (C)
