IB DP Physics Mock Exam SL Paper 1A Set 5 - 2025 Syllabus
IB DP Physics Mock Exam SL Paper 1A Set 5
Prepare for the IB DP Physics Mock Exam SL Paper 1A Set 5 with our comprehensive mock exam set 5. Test your knowledge and understanding of key concepts with challenging questions covering all essential topics. Identify areas for improvement and boost your confidence for the real exam
Question

| Option | Direction of motion of \(Q\) | Direction of travel of the wave |
|---|---|---|
| (A) | Upwards | Left to right |
| (B) | Downwards | Left to right |
| (C) | Upwards | Right to left |
| (D) | Downwards | Right to left |
▶️ Answer/Explanation
At point \(P\), the wave profile is rising (positive slope) and the particle is stated to move upwards next. For a travelling wave, if the particle motion has the same sign as the slope at that point, the wave is travelling right to left.
Point \(Q\) is also on a rising part of the wave (positive slope). With the wave travelling right to left, \(Q\) will therefore move upwards.
✅ Answer: (C)
Question
| Force on \(Q_1\) | Force on \(Q_2\) | |
|---|---|---|
| (A) | \(F\) | \(F\) |
| (B) | \(F\) | \(\frac{F}{2}\) |
| (C) | \(\frac{F}{2}\) | \(\frac{F}{2}\) |
| (D) | \(\frac{F}{2}\) | \(F\) |
▶️ Answer/Explanation
1. Apply Coulomb’s Law:
\(F \propto Q_1 Q_2\).
If \(Q_1\) is reduced to \(Q_1/2\), the new force becomes \(\frac{1}{2}F\).
2. Apply Newton’s Third Law:
The forces between two interacting charges form an action–reaction pair and are equal in magnitude.
Therefore, both \(Q_1\) and \(Q_2\) experience a force of magnitude \(\frac{F}{2}\).
✅ Answer: (C)
Question
| Number of protons | Number of neutrons | |
|---|---|---|
| (A) | \(87\) | \(139\) |
| (B) | \(87\) | \(141\) |
| (C) | \(89\) | \(139\) |
| (D) | \(89\) | \(141\) |
▶️ Answer/Explanation
1. Alpha Decay (\(_{2}^{4}\text{He}\)):
Nucleon number (A) decreases by \(4\): \(232 – 4 = 228\).
Proton number (Z) decreases by \(2\): \(90 – 2 = 88\).
2. Beta Minus Decay (\(_{-1}^{0}\beta\)):
Nucleon number (A) remains unchanged: \(228\).
Proton number (Z) increases by \(1\): \(88 + 1 = 89\).
3. Determine Protons and Neutrons:
Number of protons \(= 89\).
Number of neutrons \(= 228 – 89 = 139\).
✅ Answer: (C)
