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IB DP Physics Mock Exam SL Paper 2 Set 5 - 2025 Syllabus

IB DP Physics Mock Exam SL Paper 1B Set 5

Prepare for the IB DP Physics Mock Exam SL Paper 2 Set 5 with our comprehensive mock exam set 5. Test your knowledge and understanding of key concepts with challenging questions covering all essential topics. Identify areas for improvement and boost your confidence for the real exam

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Question 

A box of mass \( 1.2 \,\text{kg} \) is initially at rest on a horizontal surface. The coefficient of static friction between the box and the surface is \( 0.36 \) and the coefficient of dynamic friction is \( 0.28 \).
(a) Explain why coefficients of friction are dimensionless quantities. [1]
(b) Show that the smallest force required to start the box moving is approximately \( 4 \,\text{N} \). [2]
A horizontal force of \( 14.0 \,\text{N} \) is then applied to the box over a distance of \( 0.35 \,\text{m} \), as shown. The force is removed and the box continues to slide before coming to rest after an additional distance \( d \).

(c) Determine the value of \( d \). [3]
▶️ Answer/Explanation

(a)
A coefficient of friction is defined as a ratio of two forces. Since both forces are measured in newtons, the units cancel, leaving no units.

(b)
The maximum static friction is given by
\( F_{\text{max}} = \mu_s N = 0.36 \times (1.2 \times 9.8) \)
\( F_{\text{max}} = 4.23 \,\text{N} \approx 4 \,\text{N} \)

(c)
The dynamic friction force is
\( F_f = 0.28 \times 1.2 \times 9.8 = 3.29 \,\text{N} \)

Work done while the force acts over \( 0.35 \,\text{m} \):
\( W = (14.0 – 3.29) \times 0.35 = 3.75 \,\text{J} \)

This work becomes the kinetic energy of the box, which is then dissipated by friction:
\( d = \dfrac{3.75}{3.29} = 1.14 \,\text{m} \)

\( \boxed{d = 1.14 \,\text{m}} \)

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