Digital SAT Math - Non-linear equations in one variable - Easy Practice Questions - New Syllabus
DSAT MAth Practice questions – all topics
- Advanced Math Weightage: 35% Questions: 13-15
- Equivalent expressions
- Nonlinear equations in one variable and systems of equations in two variables
- Nonlinear functions
DSAT MAth and English – full syllabus practice tests
▶️ Answer/Explanation
Ans: C
The solution is the intersection point of the linear and nonlinear equations’ graphs.
The graphs intersect at \((2, 4)\).
Choices A, B, D: Incorrect, do not represent the intersection point.
▶️ Answer/Explanation
Ans: D
For \( (x + 5)^2 = 4 \):
Take square root: \( x + 5 = \pm 2 \).
Case 1: \( x + 5 = 2 \implies x = -3 \).
Case 2: \( x + 5 = -2 \implies x = -7 \).
Possible value: \( -3 \).
Choice A: Incorrect, \( (1 + 5)^2 = 36 \neq 4 \).
Choice B: Incorrect, \( (-1 + 5)^2 = 16 \neq 4 \).
Choice C: Incorrect, \( (-2 + 5)^2 = 9 \neq 4 \).
▶️ Answer/Explanation
Ans: D
The graph shows a curve decreasing toward the x-axis as \( x \) increases.
This matches a decreasing exponential function with a positive y-intercept.
Choice A: Incorrect, not a straight line.
Choice B: Incorrect, not a straight line.
Choice C: Incorrect, not increasing.
▶️ Answer/Explanation
Ans: B
The graph is an increasing exponential function. Check \( x = 0 \):
Choice A: \( y = 3^0 = 1 \)
Choice B: \( y = 2 \cdot 3^0 = 2 \)
Choice C: \( y = 2^0 = 1 \)
Choice D: \( y = 3 \cdot 2^0 = 3 \)
From the graph, at \( x = 0 \), \( y = 2 \), matching Choice B.
At \( x = 1 \), \( y \approx 6 \), and \( 2 \cdot 3^1 = 6 \), confirming Choice B.