Home / IB Mathematics SL 4.3 Measures of central tendency AI HL Paper 1- Exam Style Questions

IB Mathematics SL 4.3 Measures of central tendency AI HL Paper 1- Exam Style Questions

IB Mathematics SL 4.3 Measures of central tendency AI HL Paper 1- Exam Style Questions- New Syllabus

Question

A manufacturer of chocolates produces them in individual packets, claiming to have an average of 85 chocolates per packet. Talha bought 30 of these packets in order to check the manufacturer’s claim. Given that the number of individual chocolates is \(x\), Talha found that, from his 30 packets, \(\sum x = 2506\) and \(\sum x^2 = 209,738\).

(a) Find an unbiased estimate for the mean number (\(\mu\)) of chocolates per packet [1]

(b) Use the formula \( S^2_{n-1} = \frac{\sum x^2 – \frac{(\sum x)^2}{n}}{n-1} \) to determine an unbiased estimate for the variance of the number of chocolates per packet [2]

(c) Find a 95% confidence interval for \(\mu\). You may assume that all conditions for a confidence interval have been met [2]

(d) Suggest, with justification, a valid conclusion that Talha could make [1]

▶️ Answer/Explanation
Markscheme

(a)
83.5
Sample mean formula: \( \bar{x} = \frac{\sum x}{n} \).
Step: \( \sum x = 2506 \), \( n = 30 \), so \( \bar{x} = \frac{2506}{30} \approx 83.5333 \approx 83.5 \).
Result: 83.5 [1]

(b)
13.9
Variance formula: \( S^2_{n-1} = \frac{\sum x^2 – \frac{(\sum x)^2}{n}}{n-1} \).
Step: \( \frac{2506^2}{30} \approx 209,267.8667 \), \( \sum x^2 – \frac{(\sum x)^2}{n} = 209,738 – 209,267.8667 \approx 470.1333 \).
Step: \( \frac{470.1333}{29} \approx 13.9126 \approx 13.9 \).
Result: 13.9 [2]

(c)
(82.1, 84.9)
Confidence interval formula: \( \bar{x} \pm t \cdot \frac{s}{\sqrt{n}} \).
Step: \( s = \sqrt{13.9126} \approx 3.729 \), \( \frac{s}{\sqrt{30}} \approx 0.681 \), t-value (95%, df=29) \( \approx 2.045 \).
Step: Margin \( 2.045 \cdot 0.681 \approx 1.3927 \), interval \( 83.5333 \pm 1.3927 \approx (82.1406, 84.9260) \approx (82.1, 84.9) \).
Result: (82.1, 84.9) [2]

(d)
Talha would suggest that the manufacturer’s claim is incorrect because 85 is outside the 95% confidence interval (82.1, 84.9)
95% CI (82.1, 84.9) does not include 85, suggesting the true mean is likely not 85.
Result: Talha would suggest that the manufacturer’s claim is incorrect because 85 is outside the 95% confidence interval (82.1, 84.9) [1]

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