IB Mathematics AI SL The normal distribution MAI Study Notes - New Syllabus
IB Mathematics AI SL The normal distribution MAI Study Notes
LEARNING OBJECTIVE
- The normal distribution and curve.
Key Concepts:
- The normal distribution and curve/ Diagrammatic representation.
- Properties of the normal distribution.
- Normal probability calculations. / Inverse normal calculations
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NORMAL DISTRIBUTION
◆ Normal Distribution $N(\mu, \sigma^2)$
A normal distribution is a continuous probability distribution that is symmetric about the mean $\mu$, with a bell-shaped curve.
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It is fully defined by two parameters:
$\mu = \text{mean}, \quad \sigma = \text{standard deviation}$
$X \sim N(\mu, \sigma^2)$
The variable $X$ can take any value from $-\infty$ to $+\infty$, though practically most values lie within $\mu \pm 3\sigma$.
◆ Characteristics of the Curve
The total area under the curve is 1.
About 68% of data lies within $\mu \pm \sigma$.
About 95% lies within $\mu \pm 2\sigma$.
About 99.7% lies within $\mu \pm 3\sigma$. (Empirical Rule)
◆Applications
The normal distribution models real-world phenomena such as:
Human heights and weights
Product measurements (e.g., coffee packet mass)
Time durations (e.g., time spent in a store)
$\mathbf{GDC~ for ~Normal~ Distribution~Casio~ fx:}$
$\text{MENU → STAT → DIST → NORM → Ncd / InvN}$
| $\text{Function}$ | $\text{Use Case}$ |
| $\text{Ncd}$ | $\text{When finding a probability}$ |
| $\text{InvN}$ | $\text{When probability is given, find the value}$ |
Example
Graph and examine a situation where the mean score is 46 and the standard deviation is 8.5 for a normally distributed set of data.
▶️ Answer/Explanation
Solution:
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Examine:
What is the probability of a value falling between the mean and the first standard deviation to the right? Answer: approximately 34%
Notice how this percentage supports the information found in the chart at the top of this page for the percentage of information falling within one standard deviation above the mean.
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NORMAL PROBABILITY CALCULATION
Normal Probability Calculations
In a normally distributed dataset, the probability that a value lies within a certain range can be found using a GDC or technology. The distribution is defined as \( X \sim N(\mu, \sigma^2) \), where:
- \(\mu\) is the mean
- \(\sigma\) is the standard deviation
Probabilities such as \( P(X < a) \), \( P(X > b) \), or \( P(a < X < b) \) are computed directly using calculator functions like normalcdf without the need for standardizing to z-scores.
Example
The weights of a certain species of birds are normally distributed with mean 250g and standard deviation 15g. Find the probability that a bird weighs less than 265g.
▶️ Answer/Explanation
Solution:
Let \( X \sim N(250, 15^2) \)
We want to find \( P(X < 265) \)
Use your GDC: normalcdf(-1E99, 265, 250, 15)
Result: ≈ 0.8413
So, the probability that a bird weighs less than 265g is approximately 0.8413.
INVERSE NORMAL CALCULATION
Inverse Normal Calculations
Inverse normal calculations determine the value of the variable \( x \) given a probability. The mean and standard deviation are provided, and the technology gives the x-value directly from the cumulative area without needing to convert to a z-score.
This is typically done using the invNorm function in a GDC:
invNorm(area, μ, σ)
Note: This topic does not require transformation to the standardized variable \( z \).
The heights of students in a school are normally distributed with a mean of 170 cm and standard deviation of 8 cm. Find the height corresponding to the 90th percentile.
▶️ Answer/Explanation
Let \( X \sim N(170, 8^2) \)
We want the value of \( x \) such that \( P(X < x) = 0.90 \)
Use your GDC:
invNorm(0.90, 170, 8)Result: ≈ 180.25 cm
So, the 90th percentile corresponds to a height of approximately 180.25 cm.
